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To find Kimberlé's rate, we can calculate the distance she traveled over a known period of time. 

Here's the information given:
- After 6 hours, Kimberlé is 68 miles from her house.
- After 9 hours, she is 101 miles from her house.

We can determine how much distance she traveled between the 6th and 9th hours:

\[
\text{Distance traveled} = 101 \text{ miles} - 68 \text{ miles} = 33 \text{ miles}
\]

Next, we calculate the time over which this distance was traveled:

\[
\text{Time} = 9 \text{ hours} - 6 \text{ hours} = 3 \text{ hours}
\]

Now, the rate of speed (or Kimberlé's rate) is the distance divided by the time:

\[
\text{Rate} = \frac{\text{Distance traveled}}{\text{Time}} = \frac{33 \text{ miles}}{3 \text{ hours}} = 11 \text{ miles per hour}
\]

Therefore, Kimberlé's rate is **11 miles per hour**.

Would you like further details or have any questions?

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Here are 5 related questions that expand on the concept:
1. How would the rate change if Kimberlé traveled 40 miles in 3 hours instead of 33 miles?
2. What would her total distance be after 12 hours if she continued at the same rate?
3. How could you calculate her average speed over the entire 9-hour period?
4. How does knowing the rate help in estimating travel time for longer distances?
5. Can we determine her speed at earlier intervals (e.g., after 4 hours) based on this data?

**Tip**: When solving rate problems, always check if there are multiple intervals involved. This helps to break the problem down for better accuracy.

On a bicycle, Kimberlé rides for 6 hours and is 68 miles from her house. After riding for 9 hours, she is 101 miles away. What is Kimberlé's rate?

Learn how to calculate Kimberlé's rate of travel on a bicycle. After 6 hours of riding, she is 68 miles away from home, and after 9 hours, she is 101 miles away. This problem involves dividing distance by time to find the rate, suitable for Grades 6-8.

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