Frank's electricity bill is $62.00 this month. His electricity company charges 11.3¢/kWh. How many kilowatt hours of electrical energy can she in a month?

To calculate how many kilowatt-hours (kWh) Frank used in a month, we can use the formula:

\[
\text{Energy used (kWh)} = \frac{\text{Total cost}}{\text{Cost per kWh}}
\]

Here:
- Total cost = \$62.00
- Cost per kWh = 11.3¢ = \$0.113

Now, let's calculate:

\[
\text{Energy used (kWh)} = \frac{62.00}{0.113} \approx 548.67 \, \text{kWh}
\]

Frank used approximately **548.67 kWh** of electrical energy in a month.

Would you like further details or have any questions?

Here are 5 related questions to consider:
1. How much would Frank's bill be if he used 600 kWh?
2. What would the monthly cost be if the rate increased to 12¢/kWh?
3. How much energy would Frank use in a year at this consumption rate?
4. If the company offered a discount, charging 10¢/kWh, how much would Frank's bill be?
5. What would Frank's consumption be if his bill increased to \$100 at the same rate?

**Tip:** Always ensure units (e.g., cents to dollars) are consistent in such calculations to avoid errors.

Frank's electricity bill is $62.00 this month. His electricity company charges 11.3¢/kWh. How many kilowatt hours of electrical energy can he use in a month?

Learn how to calculate the number of kilowatt-hours (kWh) used based on an electricity bill of $62.00 with a cost of 11.3¢ per kWh. This problem involves key mathematical concepts such as division and unit conversion, suitable for students in Grades 6-8.

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