Math Problem Statement

Jack ran at 880 ft/min for the first 10 minutes of the 3 mile race before slowing his pace to finish the race with a total time of 20 minutes. What was his pace (in feet per minute) for the second part of the race?

Solution

To solve this problem, let's break down the information provided.

Step 1: Calculate the Total Distance of the Race in Feet

Since Jack is running a 3-mile race, we first convert the total distance from miles to feet: 3 miles=3×5280=15840 feet3 \text{ miles} = 3 \times 5280 = 15840 \text{ feet}

Step 2: Calculate the Distance Covered in the First 10 Minutes

Jack runs at a pace of 880 feet per minute for the first 10 minutes: Distance in first 10 minutes=880×10=8800 feet\text{Distance in first 10 minutes} = 880 \times 10 = 8800 \text{ feet}

Step 3: Calculate the Remaining Distance

Now, we subtract the distance covered in the first part from the total distance to find the distance Jack ran in the second part of the race: Remaining distance=158408800=7040 feet\text{Remaining distance} = 15840 - 8800 = 7040 \text{ feet}

Step 4: Calculate the Time Spent in the Second Part of the Race

Jack's total time for the race is 20 minutes, and he ran the first part in 10 minutes, so the time he spent on the second part is: Time for second part=2010=10 minutes\text{Time for second part} = 20 - 10 = 10 \text{ minutes}

Step 5: Calculate the Pace for the Second Part

Now we can find Jack's pace for the second part by dividing the remaining distance by the time for the second part: Pace for second part=7040 feet10 minutes=704 feet per minute\text{Pace for second part} = \frac{7040 \text{ feet}}{10 \text{ minutes}} = 704 \text{ feet per minute}

Answer

Jack’s pace for the second part of the race was 704 feet per minute.

Would you like further explanation or have any questions about this solution?

Here are 5 related questions for further practice:

  1. If Jack ran the entire 3-mile race at 880 feet per minute, how long would it take him to finish?
  2. How much time would Jack save if he maintained his initial pace for the entire race?
  3. If Jack ran a 4-mile race at the same paces as described, what would his total time be?
  4. How far would Jack cover if he maintained the slower pace (704 ft/min) for 15 minutes?
  5. If another runner finished the race in 18 minutes, what was their average pace?

Tip: When working with mixed units, like miles and feet, convert everything to a single unit to simplify calculations.

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Math Problem Analysis

Mathematical Concepts

Distance, Rate, and Time
Unit Conversion
Algebra

Formulas

Distance = Rate × Time
Conversion from miles to feet: 1 mile = 5280 feet

Theorems

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Suitable Grade Level

Grades 6-8