Math Problem Statement
Question 8 Assume the annual interest rate is 6%. Calculate the value of an investment that pays $100 every two years, starting two years from now and continuing forever.
*Make sure to input all currency answers without any currency symbols or commas, and use two decimal places of precision.
Solution
To calculate the value of an investment that pays $100 every two years indefinitely (perpetuity), we can use the formula for the present value of a perpetuity with payments made at intervals. The formula is:
However, since the payments are made every two years instead of every year, we need to adjust the interest rate accordingly. Let's proceed step by step.
Step 1: Adjust the Interest Rate
Given:
- Annual interest rate (6%)
- Payments are made every two years.
The effective interest rate for every two years (which we'll use as our discount rate) is:
But for simplicity, since the payment is every two years, the effective interest rate can also be taken as (12% every two years).
Step 2: Calculate the Present Value (PV)
The present value (PV) of a perpetuity where payments are made every two years is:
Where:
- (payment every two years)
Final Answer:
The value of the investment is 833.33.
Would you like more details on the steps? Here are some related questions for further exploration:
- How would the value change if the interest rate were compounded semi-annually?
- What if the payments were made every year instead of every two years?
- How would the investment's value be affected if the payment amount increased by a fixed percentage each period?
- Can you calculate the future value of this investment at a specific point in time?
- What is the difference in investment value when considering simple versus compound interest?
Tip: Always adjust the interest rate to match the payment interval when dealing with perpetuities or annuities.
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Math Problem Analysis
Mathematical Concepts
Finance
Perpetuity
Interest Rates
Formulas
Present Value of Perpetuity: PV = P / r
Theorems
-
Suitable Grade Level
Advanced High School
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