Math Problem Statement

Make another example of this simpler and easy to understand,What is the heat required to raise the temperature of a 1.5 kg mass by 120°C if the specific heat of the mass is 0.37cal / (g deg) * C

Solution

Q=1.5x1000 gx0.37 cal/g°C ×120°C = 66600 cal

Solution

Let's break down the problem into simpler steps:

Problem:

You want to find the amount of heat required to raise the temperature of a 1.5 kg object by 120°C. The specific heat capacity of the object is 0.37 calories per gram per degree Celsius (cal/g°C).

Step-by-step solution:

  1. Convert mass from kg to grams: Since 1 kg = 1000 grams, the mass of 1.5 kg is: 1.5kg×1000=1500grams1.5 \, \text{kg} \times 1000 = 1500 \, \text{grams}

  2. Use the heat formula: The formula to calculate the heat required is: Q=m×c×ΔTQ = m \times c \times \Delta T where:

    • QQ is the heat (in calories),
    • mm is the mass (in grams),
    • cc is the specific heat capacity (in cal/g°C),
    • ΔT\Delta T is the change in temperature (in °C).
  3. Plug in the values:

    • m=1500gm = 1500 \, \text{g},
    • c=0.37cal/g°Cc = 0.37 \, \text{cal/g°C},
    • ΔT=120°C\Delta T = 120 \, \text{°C}.

    So, the heat required is: Q=1500g×0.37cal/g°C×120°CQ = 1500 \, \text{g} \times 0.37 \, \text{cal/g°C} \times 120 \, \text{°C} Q=66600caloriesQ = 66600 \, \text{calories}

Final Answer:

The heat required is 66,600 calories.


Would you like more details or have any questions?

Here are 5 questions related to this topic:

  1. How would the heat change if the mass were 2 kg instead of 1.5 kg?
  2. What if the specific heat capacity were 0.50 cal/g°C instead of 0.37 cal/g°C?
  3. How does the heat required change if the temperature increase is 100°C instead of 120°C?
  4. What is the relationship between mass and heat required when all other factors are constant?
  5. Can the specific heat capacity change for the same material under different conditions?

Tip: Always make sure to convert units properly, like kg to grams, when using formulas!

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Math Problem Analysis

Mathematical Concepts

Heat Transfer
Unit Conversion
Specific Heat Capacity

Formulas

Q = m × c × ΔT

Theorems

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Suitable Grade Level

Grades 9-12