if my end figure is 3367, and my start figure is 190, create me a growth up to the end figure over 12 months

To calculate the growth from 190 to 3367 over 12 months, we can treat this as a case of exponential growth, assuming the growth happens at a consistent rate every month. 

The formula for exponential growth is:

\[
A = P(1 + r)^t
\]

Where:
- \( A \) is the end amount (3367),
- \( P \) is the start amount (190),
- \( r \) is the monthly growth rate,
- \( t \) is the number of months (12).

We can solve for \( r \) (the growth rate) and then apply it to find the value for each month.

Let's calculate the growth rate and the monthly figures.The monthly growth rate is approximately 27.07%. Using this growth rate, the figures for each month are:

1. Month 1: 241.43  
2. Month 2: 306.79  
3. Month 3: 389.83  
4. Month 4: 495.36  
5. Month 5: 629.44  
6. Month 6: 799.83  
7. Month 7: 1016.34  
8. Month 8: 1291.46  
9. Month 9: 1641.05  
10. Month 10: 2085.27  
11. Month 11: 2649.73  
12. Month 12: 3367.00  

Would you like more details on any step or explanation?

Here are 5 related questions:
1. What would the figures be with a different growth rate?
2. How can I calculate the total growth over the period?
3. How does compound growth differ from simple growth?
4. Can this formula be used for negative growth as well?
5. What happens if growth is not consistent?

**Tip**: Exponential growth occurs when the growth rate is applied to the existing amount, causing the quantity to increase faster over time.

This problem involves calculating the growth from 190 to 3367 over 12 months using the exponential growth formula A = P(1 + r)^t. The monthly growth rate is approximately 27.07%, and the solution provides a detailed month-by-month breakdown of the figures. Suitable for students in Grades 9-12.

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