https://file.aiquickdraw.com/mathbot/file/1730931475479m2t6jr83.jpg

To find the gravitational potential energy (\( U \)) of the can of beans, we can use the formula:

\[
U = m \cdot g \cdot h
\]

where:
- \( m \) is the mass of the can of beans, which is \( 0.425 \, \text{kg} \),
- \( g \) is the acceleration due to gravity, approximately \( 9.81 \, \text{m/s}^2 \),
- \( h \) is the height of the shelf, which is \( 2.25 \, \text{m} \).

### Calculation

Substitute the values into the formula:

\[
U = 0.425 \times 9.81 \times 2.25
\]

\[
U = 0.425 \times 22.0725
\]

\[
U \approx 9.88 \, \text{J}
\]

### Answer
The gravitational potential energy of the can of beans is approximately **9.88 J**.

Would you like a detailed explanation of gravitational potential energy or have any questions about this calculation?

Here are five related questions to further explore this topic:
1. How would the gravitational potential energy change if the can's mass were doubled?
2. What would be the potential energy if the shelf height were increased to 3 meters?
3. How does the gravitational potential energy vary with changes in gravitational acceleration?
4. What would be the impact on potential energy if the can were placed on a shelf at ground level?
5. How is gravitational potential energy different from kinetic energy?

**Tip:** Remember that gravitational potential energy depends only on the object's height above the reference point and its mass, not on its shape or volume.

A 0.425 kg can of beans sits on a 2.25 m high shelf. What is its gravitational potential energy? (Unit = J)

Find the gravitational potential energy of a 0.425 kg can of beans placed on a 2.25 m high shelf. This physics problem involves calculating potential energy using the formula U = m * g * h, where g is 9.81 m/s². Suitable for high school physics students in Grades 9-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation