To find the value of $f(8)$ for the function $f(x) = 13(2 - x)^2$, we substitute $x = 8$ into the function:

$f(8) = 13(2 - 8)^2$

Calculating $2 - 8$:

$2 - 8 = -6$

Now, square $-6$:

$(-6)^2 = 36$

Then, multiply by 13:

$f(8) = 13 \times 36 = 468$

Thus, the value of $f(8)$ is $468$.

If you have any questions or need further details, feel free to ask! Here are some related questions:

1. What is the general form of $f(x)$?
2. How does changing $x$ affect the value of $f(x)$?
3. What is the value of $f(0)$?
4. Can you find the vertex of the parabola represented by $f(x)$?
5. How would the function change if the coefficient before $(2 - x)^2$ were different?

Tip: Always check the behavior of functions at critical points to understand their shape!