For a random variable $X$ uniformly distributed on the interval $[a, b]$, the expected value $E(X)$ is calculated using the formula:

$E(X) = \frac{a + b}{2}$

In this case, $X \sim U[0, 6.1]$, so $a = 0$ and $b = 6.1$. Plugging these values into the formula:

$E(X) = \frac{0 + 6.1}{2} = \frac{6.1}{2} = 3.05$

Thus, $E(X) = 3.05$.

Let me know if you'd like more details or additional questions on uniform distribution.

Here are related questions:

1. How do you calculate the variance of $X$ for a uniform distribution?
2. What is the probability density function (PDF) of a uniform distribution?
3. How does the uniform distribution differ from other continuous distributions?
4. What is the cumulative distribution function (CDF) for a uniform distribution?
5. How is a uniform distribution used in simulation models?

Tip: For a uniform distribution, the mean is always halfway between the minimum and maximum values of the interval.