Math Problem Statement

Let X be a random variable with the following probability distribution.

Value x of X

P(X=x)

2

0.15

1

0.20

0

0.10

1

0.10

2

0.45

Complete the following. (if necessary, consult a list of formulas.)

(9) Find the expectation E(X) l X. E(X)=

(b) Find the variance Var(X) of X var(x)=

Solution

Given the probability distribution of the random variable XX, we can calculate the expectation E(X)E(X) and the variance Var(X)\text{Var}(X).

Probability Distribution:

Value xx of XXP(X=x)P(X = x)
20.15
10.20
00.10
10.10
20.45

However, notice that the values of XX have repeated probabilities. To simplify, we should group the same values of XX together:

  • For X=2X = 2: P(X=2)=0.15+0.45=0.60P(X = 2) = 0.15 + 0.45 = 0.60
  • For X=1X = 1: P(X=1)=0.20+0.10=0.30P(X = 1) = 0.20 + 0.10 = 0.30
  • For X=0X = 0: P(X=0)=0.10P(X = 0) = 0.10

Simplified Probability Distribution:

Value xx of XXP(X=x)P(X = x)
20.60
10.30
00.10

(a) Expectation E(X)E(X):

The expectation E(X)E(X) is calculated using the formula: E(X)=ixiP(X=xi)E(X) = \sum_{i} x_i \cdot P(X = x_i) Substituting the values: E(X)=(2×0.60)+(1×0.30)+(0×0.10)=1.20+0.30+0=1.50E(X) = (2 \times 0.60) + (1 \times 0.30) + (0 \times 0.10) = 1.20 + 0.30 + 0 = 1.50 So, E(X)=1.50E(X) = 1.50.

(b) Variance Var(X)\text{Var}(X):

The variance Var(X)\text{Var}(X) is calculated using the formula: Var(X)=E(X2)[E(X)]2\text{Var}(X) = E(X^2) - [E(X)]^2 First, we calculate E(X2)E(X^2): E(X2)=ixi2P(X=xi)E(X^2) = \sum_{i} x_i^2 \cdot P(X = x_i) Substituting the values: E(X2)=(22×0.60)+(12×0.30)+(02×0.10)=(4×0.60)+(1×0.30)+(0×0.10)=2.40+0.30+0=2.70E(X^2) = (2^2 \times 0.60) + (1^2 \times 0.30) + (0^2 \times 0.10) = (4 \times 0.60) + (1 \times 0.30) + (0 \times 0.10) = 2.40 + 0.30 + 0 = 2.70

Now, using E(X)=1.50E(X) = 1.50: Var(X)=E(X2)[E(X)]2=2.70(1.50)2=2.702.25=0.45\text{Var}(X) = E(X^2) - [E(X)]^2 = 2.70 - (1.50)^2 = 2.70 - 2.25 = 0.45

Final Answers:

  • E(X)=1.50E(X) = 1.50
  • Var(X)=0.45\text{Var}(X) = 0.45

Would you like more details or have any questions?

Related Questions:

  1. How do you interpret the expectation E(X)E(X) in the context of a probability distribution?
  2. How does the variance Var(X)\text{Var}(X) reflect the spread of the distribution?
  3. What is the standard deviation of XX given the variance Var(X)\text{Var}(X)?
  4. How would the expectation change if P(X=0)P(X = 0) were increased to 0.20?
  5. What is the cumulative distribution function (CDF) for this probability distribution?
  6. How do you compute E(X3)E(X^3) for this distribution?
  7. What would happen to the variance if all probabilities were uniformly distributed?
  8. How does variance relate to the concept of risk in probability?

Tip:

When calculating expectation and variance, always check for any repeated values in the distribution to simplify the calculations.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Expectation
Variance

Formulas

Expectation formula
Variance formula

Theorems

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Suitable Grade Level

College