Math Problem Statement

Pour déterminer la fem E et la résistance interne r d’une pile, on mesure la tension à ces bornes Uₚₙ et l’intensité I du courant électrique qui débite dans un circuit électrique. Données: U₁ = 4,2 V pour I₁ = 200 mA, et U₂ = 3,75 V pour I₂ = 500 mA. Calculer E, r, et l’intensité Icc du courant de court-circuit.

Solution

The exercise involves determining the electromotive force (fem) EE and the internal resistance rr of a battery based on the voltage readings at its terminals for different currents.

Here’s a breakdown of the given data:

  • When the current is I1=200mAI_1 = 200 \, \text{mA}, the terminal voltage is U1=4.2VU_1 = 4.2 \, \text{V}.
  • When the current is I2=500mAI_2 = 500 \, \text{mA}, the terminal voltage is U2=3.75VU_2 = 3.75 \, \text{V}.

We can use the formula for the terminal voltage of a battery with internal resistance: U=ErIU = E - rI Where:

  • UU is the terminal voltage
  • EE is the electromotive force (fem)
  • rr is the internal resistance
  • II is the current

From the two measurements, we can set up a system of two equations:

  1. 4.2=Er(0.2)4.2 = E - r(0.2)
  2. 3.75=Er(0.5)3.75 = E - r(0.5)

We can solve these equations to find EE and rr.

Let me proceed with solving this system. sympy import symbols, Eq, solve

Define variables

E, r = symbols('E r')

Define the equations

eq1 = Eq(E - r * 0.2, 4.2) eq2 = Eq(E - r * 0.5, 3.75)

Solve the system of equations

solution = solve((eq1, eq2), (E, r)) solutionThe solution to the system of equations is:

  • The electromotive force (fem), EE, is 4.5V4.5 \, \text{V}.
  • The internal resistance, rr, is 1.5Ω1.5 \, \Omega.

For the second part of the exercise, to calculate the short-circuit current (IccI_{\text{cc}}), where the terminal voltage is zero, we can use the formula: U=ErIU = E - rI Setting U=0U = 0 for the short-circuit condition: 0=ErIcc0 = E - rI_{\text{cc}} Solving for IccI_{\text{cc}}: Icc=ErI_{\text{cc}} = \frac{E}{r}

Let's calculate that now. Calculate the short-circuit current I_cc = solution[E] / solution[r] I_ccThe short-circuit current (IccI_{\text{cc}}) is 3.0A3.0 \, \text{A}.

Would you like further details or clarification on any part of this calculation? Here are some related questions:

  1. How does the internal resistance affect the performance of the battery in a circuit?
  2. What would happen to the terminal voltage if the current were even higher?
  3. How can we determine the efficiency of a battery based on these measurements?
  4. What is the impact of a very low internal resistance on battery life?
  5. How do we calculate the power dissipated in the internal resistance?

Tip: When calculating the short-circuit current, remember that it assumes zero terminal voltage, which typically happens when a battery is directly connected to a low-resistance load.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Ohm's Law

Formulas

U = E - rI
Icc = E / r

Theorems

Ohm's Law

Suitable Grade Level

Grades 10-12