For the situation below, assuming each positive and negative charges has a magnitude of 1 nC, calculate the force of attraction (in Newtons) between the jacket and the balloon. Assume the two charged objects are separated a distance of 6.5cm.

Given the scenario where each positive and negative charge has a magnitude of \( q = 1 \, \text{nC} \) (nanocoulomb), and the distance between the jacket and the balloon is \( r = 6.5 \, \text{cm} \) (which is 0.065 meters), we can calculate the electrostatic force of attraction using **Coulomb's Law**.

### Coulomb's Law Formula:
\[
F = k \cdot \frac{|q_1 \cdot q_2|}{r^2}
\]

Where:
- \( k \) is Coulomb's constant: \( 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \)
- \( q_1 = q_2 = 1 \, \text{nC} = 1 \times 10^{-9} \, \text{C} \)
- \( r = 0.065 \, \text{m} \)

### Substituting the values:
\[
F = 8.99 \times 10^9 \times \frac{(1 \times 10^{-9}) \times (1 \times 10^{-9})}{(0.065)^2}
\]

\[
F = 8.99 \times 10^9 \times \frac{1 \times 10^{-18}}{0.004225}
\]

\[
F = 8.99 \times 10^9 \times 2.367 \times 10^{-16}
\]

\[
F = 2.127 \times 10^{-6} \, \text{N}
\]

### Final Answer:
The electrostatic force of attraction between the jacket and the balloon is approximately **\( 2.13 \times 10^{-6} \, \text{N} \)**.

Would you like more details or have any questions?

### Relative Questions:
1. How would the force change if the distance was reduced to 3.25 cm?
2. What if the magnitude of each charge was doubled to 2 nC?
3. How does this force compare to gravitational forces typically experienced by everyday objects?
4. What would be the impact if the charges were located in a different medium, such as water?
5. How can you determine the direction of the force in cases where the charges are not symmetrical?

### Tip:
In electrostatics problems, always ensure to convert units correctly, especially distances from centimeters to meters, as the formula depends on the SI unit system.

Learn how to calculate the electrostatic force of attraction between a jacket and a balloon with charges of 1 nC each, separated by 6.5 cm. This problem uses Coulomb's Law and involves conversion of units from centimeters to meters. Suitable for advanced high school students.

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