Math Problem Statement

A 400-foot tall l monument is located in the distance. From a window in a building, a person determines that the angle of elevation to the top of the monument is 18°, and that the angle of the depression to the bottom of the. monument is 3°. How far is the person from the monument?

Solution

To find how far the person is from the monument, we can use trigonometric relationships based on the angles of elevation and depression.

Step 1: Define variables

Let:

  • dd be the horizontal distance from the person to the monument.
  • hh be the height of the building window from which the person is viewing the monument.
  • The monument's height is given as 400 feet.

The angle of elevation to the top of the monument is 18°, and the angle of depression to the bottom of the monument is 3°.

Step 2: Use trigonometry to set up equations

We can break this problem into two right triangles:

  1. Top of the monument: The angle of elevation to the top of the monument is 18°, and the height difference between the person and the top of the monument is 400h400 - h.
  2. Bottom of the monument: The angle of depression to the bottom of the monument is 3°, and the height difference between the person and the ground (bottom of the monument) is hh.

Using the tangent function:

  • For the top triangle: tan(18)=400hd\tan(18^\circ) = \frac{400 - h}{d} Rearranging, we get: d=400htan(18)d = \frac{400 - h}{\tan(18^\circ)}

  • For the bottom triangle: tan(3)=hd\tan(3^\circ) = \frac{h}{d} Rearranging, we get: d=htan(3)d = \frac{h}{\tan(3^\circ)}

Step 3: Set up an equation

Since both expressions represent the same distance dd, we can set them equal to each other: 400htan(18)=htan(3)\frac{400 - h}{\tan(18^\circ)} = \frac{h}{\tan(3^\circ)}

Step 4: Solve for hh

Now, solve this equation for hh: (400h)tan(3)=htan(18)(400 - h)\tan(3^\circ) = h\tan(18^\circ) Expanding: 400tan(3)htan(3)=htan(18)400\tan(3^\circ) - h\tan(3^\circ) = h\tan(18^\circ) Move terms involving hh to one side: 400tan(3)=h(tan(18)+tan(3))400\tan(3^\circ) = h(\tan(18^\circ) + \tan(3^\circ)) Solve for hh: h=400tan(3)tan(18)+tan(3)h = \frac{400\tan(3^\circ)}{\tan(18^\circ) + \tan(3^\circ)}

Step 5: Calculate values

Using a calculator:

  • tan(18)0.3249\tan(18^\circ) \approx 0.3249
  • tan(3)0.05241\tan(3^\circ) \approx 0.05241

Substitute these values into the equation: h=400×0.052410.3249+0.0524120.9640.3773155.56feeth = \frac{400 \times 0.05241}{0.3249 + 0.05241} \approx \frac{20.964}{0.37731} \approx 55.56 \, \text{feet}

Step 6: Find dd

Now that we know hh, we can substitute it back into the expression for dd: d=55.56tan(3)55.560.052411,059.76feetd = \frac{55.56}{\tan(3^\circ)} \approx \frac{55.56}{0.05241} \approx 1,059.76 \, \text{feet}

Final Answer:

The person is approximately 1,059.76 feet from the monument.


Would you like further clarification on any of the steps or details?

Here are some related questions:

  1. What if the height of the monument were different? How would the distance change?
  2. How would the calculations change if the angles of elevation and depression were reversed?
  3. Can we apply the same principles to calculate the height of the building?
  4. How does changing the angle of elevation affect the horizontal distance?
  5. What is the relationship between the tangent function and right triangles in this context?

Tip: Always double-check your trigonometric functions and ensure your calculator is in degree mode when working with angles in degrees!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangles
Angle of Elevation
Angle of Depression

Formulas

tan(θ) = opposite / adjacent
d = (400 - h) / tan(18°)
d = h / tan(3°)
h = (400 * tan(3°)) / (tan(18°) + tan(3°))

Theorems

Right Triangle Trigonometry

Suitable Grade Level

Grades 9-12