Math Problem Statement

Point A and point B have been plotted on a centimetre square grid. Point A has coordinates (2, 3) and point B has coordinates (7, 9). Using Pythagoras' theorem, calculate the distance from A to B. Give your answer in centimetres (cm) to 1 d.p.

Solution

The problem asks to calculate the distance between points A and B using Pythagoras' theorem.

Given:

  • Coordinates of point A: (2,3)(2, 3)
  • Coordinates of point B: (7,9)(7, 9)

Pythagoras' theorem:

The distance dd between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substituting the coordinates of A and B: d=(72)2+(93)2=52+62=25+36=61d = \sqrt{(7 - 2)^2 + (9 - 3)^2} = \sqrt{5^2 + 6^2} = \sqrt{25 + 36} = \sqrt{61}

Now, let's calculate the exact value of 61\sqrt{61}.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, I can continue with the calculation manually:

617.81\sqrt{61} \approx 7.81

So, the distance between point A and point B is approximately 7.8 cm, rounded to 1 decimal place.

Would you like more details on this or have any questions?

Here are 5 related questions to expand on this:

  1. How do you apply Pythagoras' theorem to real-world problems?
  2. Can this method be used to calculate distances in three-dimensional space?
  3. What other methods can be used to find the distance between two points?
  4. How does the distance formula relate to the equation of a circle?
  5. How would you calculate the midpoint between two points?

Tip: Always remember to square the differences before summing them in the distance formula!

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Pythagoras' Theorem

Formulas

d = √((x2 - x1)² + (y2 - y1)²)

Theorems

Pythagoras' Theorem

Suitable Grade Level

Grades 7-9