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The problem asks to calculate the distance between points A and B using Pythagoras' theorem.

### Given:
- Coordinates of point A: \( (2, 3) \)
- Coordinates of point B: \( (7, 9) \)

### Pythagoras' theorem:
The distance \( d \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by the formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Substituting the coordinates of A and B:
\[
d = \sqrt{(7 - 2)^2 + (9 - 3)^2} = \sqrt{5^2 + 6^2} = \sqrt{25 + 36} = \sqrt{61}
\]

Now, let's calculate the exact value of \( \sqrt{61} \).It seems like I can’t do more advanced data analysis right now. Please try again later.

However, I can continue with the calculation manually:

\[
\sqrt{61} \approx 7.81
\]

So, the distance between point A and point B is approximately **7.8 cm**, rounded to 1 decimal place.

Would you like more details on this or have any questions?

Here are 5 related questions to expand on this:
1. How do you apply Pythagoras' theorem to real-world problems?
2. Can this method be used to calculate distances in three-dimensional space?
3. What other methods can be used to find the distance between two points?
4. How does the distance formula relate to the equation of a circle?
5. How would you calculate the midpoint between two points?

**Tip:** Always remember to square the differences before summing them in the distance formula!

Point A and point B have been plotted on a centimetre square grid. Point A has coordinates (2, 3) and point B has coordinates (7, 9). Using Pythagoras' theorem, calculate the distance from A to B. Give your answer in centimetres (cm) to 1 d.p.

Learn how to calculate the distance between two points on a coordinate plane using Pythagoras' theorem. This example shows how to find the distance between point A (2, 3) and point B (7, 9) by applying the distance formula. Suitable for students in Grades 7-9.

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