Math Problem Statement

An object begins at point A and moves to point B. How far did the object travel? Round your answer to one decimal place.

Solution

To find the distance the object traveled from point AA to point BB on the graph, we can use the distance formula between two points in a coordinate plane. The formula is:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step 1: Identify Coordinates of Points AA and BB

From the graph:

  • Point AA has coordinates (5,5)(-5, -5).
  • Point BB has coordinates (4,3)(4, 3).

Step 2: Substitute the Values into the Distance Formula

Using (x1,y1)=(5,5)(x_1, y_1) = (-5, -5) and (x2,y2)=(4,3)(x_2, y_2) = (4, 3):

d=(4(5))2+(3(5))2d = \sqrt{(4 - (-5))^2 + (3 - (-5))^2} =(4+5)2+(3+5)2= \sqrt{(4 + 5)^2 + (3 + 5)^2} =(9)2+(8)2= \sqrt{(9)^2 + (8)^2} =81+64= \sqrt{81 + 64} =145= \sqrt{145}

Step 3: Calculate and Round the Distance

d12.0d \approx 12.0

Final Answer:

The distance the object traveled is approximately 12.0 miles.

Would you like more details on any steps or have any questions?


Here are five related questions for further exploration:

  1. How would the distance change if the coordinates of point AA or BB were altered slightly?
  2. How do we interpret the distance formula in terms of the Pythagorean theorem?
  3. What would happen if each grid square represented 0.5 miles instead of 1 mile?
  4. How can we find the midpoint between points AA and BB?
  5. Can this distance formula be extended to three-dimensional space?

Tip: Always double-check coordinate values when reading from a graph to ensure accuracy in calculations.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Calculation

Formulas

Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10