Math Problem Statement

Find the distance, d, of AB. A = (1, 0) B = (5, 2)

Solution

The problem asks to find the distance dd between two points A(1,0)A(1, 0) and B(5,2)B(5, 2) using the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Where:

  • A(x1,y1)=(1,0)A(x_1, y_1) = (1, 0)
  • B(x2,y2)=(5,2)B(x_2, y_2) = (5, 2)

Substituting these coordinates into the formula:

d=(51)2+(20)2d = \sqrt{(5 - 1)^2 + (2 - 0)^2}

d=(4)2+(2)2d = \sqrt{(4)^2 + (2)^2}

d=16+4d = \sqrt{16 + 4}

d=20d = \sqrt{20}

d4.47d \approx 4.47

Rounded to the nearest tenth, the distance dd is approximately 4.54.5.

Would you like more details or have any further questions?

Here are 5 related questions for further understanding:

  1. What is the significance of using the distance formula in coordinate geometry?
  2. How does the distance formula relate to the Pythagorean theorem?
  3. Can the distance between points be negative, and why or why not?
  4. How would the formula change if we were working in three dimensions?
  5. What are the coordinates of the midpoint between points A and B?

Tip: Always verify that the coordinates are accurately substituted into the distance formula to avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Formula

Formulas

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 6-8