A boy walks due West and 10 m due South what is the displacement of the boy

The displacement of the boy can be found using the Pythagorean theorem, as the movement creates a right triangle.

1. The boy walks **10 meters west** and then **10 meters south**.
2. We consider the westward and southward movements as the two legs of a right triangle.

Using the Pythagorean theorem:
\[
\text{Displacement} = \sqrt{(10^2 + 10^2)}
\]

Calculating this:
\[
\text{Displacement} = \sqrt{100 + 100} = \sqrt{200} = 10\sqrt{2} \approx 14.14 \text{ meters}
\]

### Answer
The boy’s displacement is approximately **14.14 meters** southwest.

Would you like more details or have any questions?

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1. What if the boy walked different distances west and south?
2. How would displacement change if he walked diagonally?
3. How does displacement differ from total distance traveled?
4. What if the boy walked in three directions instead of two?
5. How would displacement be calculated if he moved in a circle?

**Tip:** Remember that displacement is always the shortest distance between the start and end points, regardless of the path taken.

Learn how to calculate the displacement of a boy walking 10 meters west and 10 meters south using the Pythagorean theorem. This step-by-step solution covers key geometry concepts, including distance and displacement. Ideal for students in Grades 6-8.

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