We are asked to find the distance the players ran along the diagonal of a rectangular football field twice.

Step 1: Use the Pythagorean theorem

Since the field is a rectangle, the diagonal $d$ can be found using the Pythagorean theorem: $d = \sqrt{L^2 + W^2}$ where:

• $L = 100 \, \text{yards}$ (the length),
• $W = 53.3 \, \text{yards}$ (the width).

Step 2: Plug in the values

$d = \sqrt{100^2 + 53.3^2}$ $d = \sqrt{10000 + 2840.89}$ $d = \sqrt{12840.89}$ $d \approx 113.33 \, \text{yards}$

Step 3: Double the diagonal distance

The players ran along the diagonal twice: $\text{Total distance} = 2 \times 113.33 \approx 226.66 \, \text{yards}$

Thus, the answer is approximately 226.66 yards.

Do you need more details or have any questions?

Here are 5 related questions to expand the concept:

1. How would the diagonal change if the width of the field increased by 10 yards?
2. What if the players only ran the diagonal once; what distance would they cover?
3. If the players ran four times along the diagonal, what would the total distance be?
4. How does the Pythagorean theorem help in real-world applications like this?
5. What if the field had a different shape, like a square? How would you find the diagonal then?

Tip: When solving for the diagonal of a rectangle, the Pythagorean theorem is a quick and reliable method!