Math Problem Statement

The age of a person on 28-02-1978 was 12 years 5month 18 days. What was his DOB?

Solution

To calculate the date of birth, subtract the age (12 years, 5 months, and 18 days) from the given date (28-02-1978).

Step 1: Subtract the days

  • Starting date: 28 February 1978
  • Subtract 18 days: 2818=1028 - 18 = 10
  • Resulting date: 10 February 1978

Step 2: Subtract the months

  • Starting month: February 1978
  • Subtract 5 months: From February, count backward 5 months (February → January → December → November → October → September)
  • Resulting month: September 1977

Step 3: Subtract the years

  • Starting year: 1977
  • Subtract 12 years: 197712=19651977 - 12 = 1965

Final Result:

The person’s date of birth is 10 September 1965.

Would you like a detailed explanation or have further questions?


Here are 5 related questions for better understanding:

  1. How do leap years affect such calculations?
  2. What if the calculation spans across centuries?
  3. How can such a calculation be automated using a formula?
  4. How is age typically calculated in different calendars (e.g., Gregorian vs. Lunar)?
  5. How to account for varying days in months for manual calculations?

Tip: Always verify results by adding the calculated age to the date of birth to ensure the end date matches.

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Math Problem Analysis

Mathematical Concepts

Date Arithmetic
Subtraction of Dates

Formulas

Subtract days from the given date
Subtract months while accounting for year transitions
Subtract years from the resulting year

Theorems

Basic Arithmetic Rules for Date Calculation

Suitable Grade Level

Grades 6-8