The problem shows a square plot of land $PQRS$ with a small rectangular region fenced off for planting. The fencing cost is RM 40 per meter, and the goal is to calculate the total cost of fencing the colored region.

From the diagram, we can observe:

• The larger square $PQRS$ has equal sides, and the side length of $PQ$ (or $PS$) is 10 meters (from point $S$ to $R$).
• The smaller rectangle $PNML$ has dimensions of 5 meters along $PQ$ and 6 meters along $PS$, meaning $PN = 5$ meters and $PL = 6$ meters.
• The colored region being fenced seems to encompass the portion of $PQRS$ minus the small rectangular region $PNML$.

Step-by-step approach:

1. The fence follows the boundaries of the L-shaped region formed by subtracting the rectangle from the square.
2. To find the total length of the fencing needed, sum the sides along which the fence is constructed.

• Side $L$ to $S$ = 6 meters
• Side $S$ to $J$ = 6 meters (along $SR$)
• Side $J$ to $K$ = 10 meters
• Side $K$ to $Q$ = $5$ meters

Total length of fencing:

The perimeter is $6 + 6 + 10 + 5 = 27$ meters.

Cost:

The cost of fencing is RM 40 per meter. Therefore, the total cost is: $\text{Total cost} = 27 \times 40 = \text{RM } 1080$

Thus, Susan must pay RM 1080 to fence the region.

Would you like a more detailed explanation of any part of the solution?

Here are five related questions to expand on this:

1. How do you calculate the perimeter of irregular regions?
2. What is the formula for the perimeter of a square and rectangle?
3. If the cost per meter increases, how would that affect the total fencing cost?
4. How would the problem change if the rectangular region was also fenced?
5. What methods can be used to calculate the area of the fenced region?

Tip: Always ensure you double-check measurements and unit conversions in problems involving geometry to avoid simple mistakes.