To find the value of \(\cos(-\pi)\), we can use the fact that the cosine function is an even function. This means that \(\cos(-x) = \cos(x)\). Therefore:

\[
\cos(-\pi) = \cos(\pi)
\]

Now, we know from the unit circle that:

\[
\cos(\pi) = -1
\]

Thus:

\[
\cos(-\pi) = -1
\]

So, the value of \(\cos(-\pi)\) is \(-1\).

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### Related Questions:

1. What is the value of \(\sin(-\pi)\)?
2. How do you prove that the cosine function is even?
3. What is the value of \(\cos(\pi/2)\)?
4. How does the unit circle help in finding trigonometric values?
5. What are the values of cosine and sine at \(-\frac{\pi}{4}\)?

### Tip:
Remember that \(\cos(\theta)\) is an even function, so \(\cos(-\theta) = \cos(\theta)\), while \(\sin(\theta)\) is an odd function, so \(\sin(-\theta) = -\sin(\theta)\).

Discover how to calculate the value of cos(−𝜋) using trigonometric identities. This solution explores the properties of even functions, such as cosine, and how the unit circle is utilized to find trigonometric values. Suitable for students in Grades 9-12.

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