Math Problem Statement

Based on the data shown below, calculate the correlation coefficient (rounded to three decimal places)

x y 5 46.95 6 43.7 7 40.75 8 36.2 9 34.35 10 32.6 11 30.65 12 27.1 13 25.65 14 20.3 15 18.65 16 17.2

Solution

To calculate the correlation coefficient (rr) between xx and yy, we use the formula:

r=(xixˉ)(yiyˉ)(xixˉ)2(yiyˉ)2r = \frac{\sum{(x_i - \bar{x})(y_i - \bar{y})}}{\sqrt{\sum{(x_i - \bar{x})^2} \cdot \sum{(y_i - \bar{y})^2}}}

Step-by-step process:

  1. Compute the means of xx and yy: xˉ=xin,yˉ=yin\bar{x} = \frac{\sum{x_i}}{n}, \quad \bar{y} = \frac{\sum{y_i}}{n}

  2. Calculate deviations from the mean: For each xix_i and yiy_i, calculate: (xixˉ)and(yiyˉ)(x_i - \bar{x}) \quad \text{and} \quad (y_i - \bar{y})

  3. Compute the cross-product of deviations and square of deviations: Calculate: (xixˉ)(yiyˉ),(xixˉ)2,and(yiyˉ)2(x_i - \bar{x})(y_i - \bar{y}), \quad (x_i - \bar{x})^2, \quad \text{and} \quad (y_i - \bar{y})^2

  4. Substitute into the correlation formula:

    • Numerator: Sum of (xixˉ)(yiyˉ)(x_i - \bar{x})(y_i - \bar{y})
    • Denominator: Square root of the product of (xixˉ)2\sum{(x_i - \bar{x})^2} and (yiyˉ)2\sum{(y_i - \bar{y})^2}

Let's calculate this step-by-step! numpy as np

Data points

x = np.array([5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]) y = np.array([46.95, 43.7, 40.75, 36.2, 34.35, 32.6, 30.65, 27.1, 25.65, 20.3, 18.65, 17.2])

Calculate means

mean_x = np.mean(x) mean_y = np.mean(y)

Calculate deviations

x_deviation = x - mean_x y_deviation = y - mean_y

Calculate terms

numerator = np.sum(x_deviation * y_deviation) denominator = np.sqrt(np.sum(x_deviation2) * np.sum(y_deviation2))

Correlation coefficient

r = numerator / denominator r_rounded = round(r, 3) r_roundedThe correlation coefficient rr between xx and yy is approximately 0.995-0.995. This indicates a very strong negative linear relationship between the two variables.

Would you like further explanation or details about the calculation? Here are some related questions for exploration:

  1. How does a correlation coefficient of 0.995-0.995 affect predictions between xx and yy?
  2. Can we derive the line of best fit for these data points?
  3. What would happen to rr if the data included significant outliers?
  4. How does this result compare to a perfect correlation of 1-1?
  5. What are the limitations of correlation analysis?

Tip: Always visualize the data with a scatter plot to confirm the linearity of the relationship when interpreting rr.

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Math Problem Analysis

Mathematical Concepts

Statistics
Correlation Analysis
Linear Relationships

Formulas

Correlation coefficient formula: r = Σ((x_i - x̄)(y_i - ȳ)) / √(Σ(x_i - x̄)^2 * Σ(y_i - ȳ)^2)

Theorems

Properties of Correlation Coefficient

Suitable Grade Level

Grades 10-12