Math Problem Statement

A study of bone density on 5 random women at a hospital produced the following results.

Age 37 41 45 65 69 Bone Density 355 350 335 330 320

Step 3 of 3 : Calculate the correlation coefficient, r. Round your answer to three decimal places.

Solution

To calculate the correlation coefficient rr, we can use the following formula:

[ r = \frac{n \sum{xy} - (\sum{x})(\sum{y})}{\sqrt{[n \sum{x^2} - (\sum{x})^2][n \sum{y^2} - (\sum{y})^2]}} ]

Where:

  • nn is the number of data points (5 in this case),
  • xx represents the age values,
  • yy represents the bone density values,
  • \sum represents the summation over all data points.

Step 1: Organize the Data

The data provided is as follows:

Age xxBone Density yy
37355
41350
45335
65330
69320

Step 2: Calculate the necessary sums

First, calculate the following:

  1. x\sum{x}
  2. y\sum{y}
  3. xy\sum{xy}
  4. x2\sum{x^2}
  5. y2\sum{y^2}

Let’s compute these values:

  • x=37+41+45+65+69=257\sum{x} = 37 + 41 + 45 + 65 + 69 = 257
  • y=355+350+335+330+320=1690\sum{y} = 355 + 350 + 335 + 330 + 320 = 1690
  • xy=(37×355)+(41×350)+(45×335)+(65×330)+(69×320)\sum{xy} = (37 \times 355) + (41 \times 350) + (45 \times 335) + (65 \times 330) + (69 \times 320)
  • x2=(372)+(412)+(452)+(652)+(692)\sum{x^2} = (37^2) + (41^2) + (45^2) + (65^2) + (69^2)
  • y2=(3552)+(3502)+(3352)+(3302)+(3202)\sum{y^2} = (355^2) + (350^2) + (335^2) + (330^2) + (320^2)

Let me compute the individual calculations for these values. Data ages = [37, 41, 45, 65, 69] bone_densities = [355, 350, 335, 330, 320]

Calculate necessary sums

sum_x = sum(ages) sum_y = sum(bone_densities) sum_x2 = sum(x2 for x in ages) sum_y2 = sum(y2 for y in bone_densities) sum_xy = sum(ages[i] * bone_densities[i] for i in range(len(ages)))

Number of data points

n = len(ages)

(sum_x, sum_y, sum_xy, sum_x2, sum_y2)The computed values are:

  • x=257\sum{x} = 257
  • y=1690\sum{y} = 1690
  • xy=86090\sum{xy} = 86090
  • x2=14061\sum{x^2} = 14061
  • y2=572050\sum{y^2} = 572050

Step 3: Plug the values into the correlation coefficient formula

Now we can substitute these values into the formula for the correlation coefficient rr:

[ r = \frac{5(86090) - (257)(1690)}{\sqrt{[5(14061) - (257)^2][5(572050) - (1690)^2]}} ]

Let me compute this for you. math

Calculate the numerator and denominator of the correlation coefficient formula

numerator = (n * sum_xy) - (sum_x * sum_y) denominator = math.sqrt((n * sum_x2 - sum_x2) * (n * sum_y2 - sum_y2))

Calculate the correlation coefficient

r = numerator / denominator round(r, 3)The correlation coefficient rr is approximately -0.923.

This indicates a strong negative linear relationship between age and bone density in this sample.

Do you need further explanation or assistance with any other steps? Here are some related questions you might find useful:

  1. What does a negative correlation coefficient signify in the context of this study?
  2. How do you interpret the strength of the correlation based on the value of rr?
  3. How would you calculate the regression line using this data?
  4. How does the correlation coefficient change if we remove the outlier (65 years, 330 bone density)?
  5. What is the significance of correlation in medical studies?

Tip: Always visualize the data (scatter plot) when checking the strength of correlation to better understand the relationship.

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Math Problem Analysis

Mathematical Concepts

Statistics
Correlation Coefficient
Linear Relationship

Formulas

r = (n * Σxy - Σx * Σy) / √[(n * Σx² - (Σx)²)(n * Σy² - (Σy)²)]

Theorems

Pearson's Correlation Coefficient

Suitable Grade Level

Grades 10-12