Math Problem Statement

Complete the table by finding the balance A when P dollars is invested at rate r for t years and compounded n times per year. (Round your answers to the nearest cent.) P = $5000, r = 2%, t = 20 years continus

Solution

To complete this, we'll use the formula for continuous compounding, since it's compounded continuously. The formula is:

A=PertA = Pe^{rt}

where:

  • P=5000P = 5000 (principal),
  • r=0.02r = 0.02 (interest rate as a decimal),
  • t=20t = 20 (time in years),
  • e2.71828e \approx 2.71828 (base of the natural logarithm).

Step-by-Step Calculation

  1. Substitute the values into the formula: A=5000e(0.02×20)A = 5000 \cdot e^{(0.02 \times 20)}

  2. Calculate the exponent: 0.02×20=0.40.02 \times 20 = 0.4

  3. Now, find e0.4e^{0.4}: e0.41.4918e^{0.4} \approx 1.4918

  4. Multiply by the principal: A=50001.49187459.00A = 5000 \cdot 1.4918 \approx 7459.00

So, the balance AA after 20 years is approximately $7459.00.

Would you like further details on any steps?


Further Related Questions

  1. How does continuous compounding differ from other compounding frequencies?
  2. What would the balance be if compounded annually instead?
  3. How would the balance change with a different interest rate?
  4. What if the investment duration was shorter, such as 10 years?
  5. How does compounding impact the total balance over long-term investments?

Tip

Continuous compounding yields slightly higher returns than periodic compounding due to constant reinvestment of interest.

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Math Problem Analysis

Mathematical Concepts

Continuous Compounding
Exponential Growth

Formulas

A = Pe^{rt}

Theorems

Compound Interest Theorem

Suitable Grade Level

Grades 10-12