Math Problem Statement

A sugar solution was made by mixing 8qt of a 2% sugar solution and 6qt of a 51% sugar solution. Find the concentration of the new mixture.

Solution

To find the concentration of the new mixture, we need to calculate the total amount of sugar in the solution and divide it by the total volume of the mixture.

Step-by-Step Solution:

  1. Calculate the amount of sugar in each solution:

    • For the 2% sugar solution: Amount of sugar=8qt×2100=0.16qt\text{Amount of sugar} = 8 \, \text{qt} \times \frac{2}{100} = 0.16 \, \text{qt}

    • For the 51% sugar solution: Amount of sugar=6qt×51100=3.06qt\text{Amount of sugar} = 6 \, \text{qt} \times \frac{51}{100} = 3.06 \, \text{qt}

  2. Calculate the total amount of sugar in the mixture:

    Total sugar=0.16qt+3.06qt=3.22qt\text{Total sugar} = 0.16 \, \text{qt} + 3.06 \, \text{qt} = 3.22 \, \text{qt}

  3. Calculate the total volume of the mixture:

    Total volume=8qt+6qt=14qt\text{Total volume} = 8 \, \text{qt} + 6 \, \text{qt} = 14 \, \text{qt}

  4. Calculate the concentration of the new mixture:

    Concentration=(Total sugarTotal volume)×100=(3.22qt14qt)×100\text{Concentration} = \left( \frac{\text{Total sugar}}{\text{Total volume}} \right) \times 100 = \left( \frac{3.22 \, \text{qt}}{14 \, \text{qt}} \right) \times 100

    Concentration=(0.23)×100=23%\text{Concentration} = \left(0.23\right) \times 100 = 23\%

Conclusion:

The concentration of the new mixture is 23%.

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:

  1. How would the concentration change if we used different volumes of each solution?
  2. What if we mixed a 10% sugar solution instead of a 51% one?
  3. How can you find the volume of a specific concentration needed to achieve a target mixture concentration?
  4. How would you create a 10% solution by mixing a 2% and a 51% solution?
  5. How does dilution affect the concentration of a solution?

Tip: Always ensure the units match when performing mixture calculations to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Percentage
Mixture Problems
Ratio and Proportion

Formulas

Concentration of a mixture = (Total sugar / Total volume) × 100

Theorems

Law of Mixtures

Suitable Grade Level

Grades 7-9