Math Problem Statement

Question 9

Leigh borrows $35 000 to complete home renovations. Compound interest will be charged at the rate of 4.6% per annum, compounding monthly.

If Leigh makes monthly payments of $1529.24, the amount of interest he has paid after one year is closest to:

$1253

B. $1610

C. $16 649

D. $17 098

E. $18 350

Question 10

Henri is considering a 5-year interest-only loan for a car valued at $30,000. The loan has a fixed interest rate of 8% per year compounded monthly. After 3 years, how much would Henri still owe on his loan?

A. $12,000

В. $13449.66

C. $2264.50

D. $25,521.26

E. $30,000

Solution

Question 9

To determine the amount of interest Leigh has paid after one year, we need to break down the total amount paid and the principal repaid.

Given:

  • Principal P=$35,000P = \$35,000
  • Annual interest rate r=4.6%r = 4.6\%
  • Monthly payment R=$1529.24R = \$1529.24
  • Loan period for interest calculation = 1 year

Step 1: Convert annual interest rate to monthly rate rmonthly=4.6%12=0.046120.003833r_{\text{monthly}} = \frac{4.6\%}{12} = \frac{0.046}{12} \approx 0.003833

Step 2: Calculate total payments made in one year Total payments=1529.24×12=18,350.88\text{Total payments} = 1529.24 \times 12 = 18,350.88

Step 3: Calculate the balance after one year Using the formula for the remaining balance on an amortizing loan: B=P×(1+rmonthly)12Rrmonthly×[(1+rmonthly)121]B = P \times (1 + r_{\text{monthly}})^{12} - \frac{R}{r_{\text{monthly}}} \times \left[(1 + r_{\text{monthly}})^{12} - 1\right]

B=35000×(1+0.003833)121529.240.003833×[(1+0.003833)121]B = 35000 \times (1 + 0.003833)^{12} - \frac{1529.24}{0.003833} \times \left[(1 + 0.003833)^{12} - 1\right]

First, calculate (1+0.003833)12(1 + 0.003833)^{12}: (1+0.003833)121.047(1 + 0.003833)^{12} \approx 1.047

Now, calculate the balance BB: B=35000×1.0471529.240.003833×(1.0471)B = 35000 \times 1.047 - \frac{1529.24}{0.003833} \times (1.047 - 1)

B=366451529.240.003833×0.047B = 36645 - \frac{1529.24}{0.003833} \times 0.047

B=36645398868.81×0.0473664518746.64=17898.36B = 36645 - 398868.81 \times 0.047 \approx 36645 - 18746.64 = 17898.36

Step 4: Calculate the total principal repaid in one year Principal repaid=3500017898.36=17101.64\text{Principal repaid} = 35000 - 17898.36 = 17101.64

Step 5: Calculate the total interest paid in one year Total interest paid=Total paymentsPrincipal repaid\text{Total interest paid} = \text{Total payments} - \text{Principal repaid}

Total interest paid=18350.8817101.64=1249.24\text{Total interest paid} = 18350.88 - 17101.64 = 1249.24

Thus, the closest answer is: A.1253\boxed{A. \, 1253}

Question 10

Henri is considering a 5-year interest-only loan for a car valued at $30,000 with a fixed interest rate of 8% per year compounded monthly.

Given:

  • Principal P=$30,000P = \$30,000
  • Annual interest rate r=8%r = 8\%
  • Loan term = 5 years
  • Time passed = 3 years

For an interest-only loan, the principal does not reduce over the life of the loan. The borrower only pays the interest periodically.

Step 1: Convert annual interest rate to monthly rate rmonthly=8%12=0.08120.006667r_{\text{monthly}} = \frac{8\%}{12} = \frac{0.08}{12} \approx 0.006667

Step 2: Calculate the monthly interest payment Monthly interest payment=P×rmonthly=30000×0.006667=200\text{Monthly interest payment} = P \times r_{\text{monthly}} = 30000 \times 0.006667 = 200

Step 3: Calculate the total interest paid after 3 years Total interest paid in 3 years=200×12×3=7200\text{Total interest paid in 3 years} = 200 \times 12 \times 3 = 7200

Since this is an interest-only loan, the principal remains unchanged, so Henri would still owe the original loan amount: E.30000\boxed{E. \, 30000}

Would you like more details or have any questions?

Here are 8 related questions:

  1. What is the difference between an interest-only loan and an amortizing loan?
  2. How does compounding frequency affect the total interest paid on a loan?
  3. What would be the monthly payments for a fully amortizing loan of $30,000 at 8% over 5 years?
  4. How do you calculate the remaining balance on an amortizing loan?
  5. How can you determine the total interest paid over the life of a loan?
  6. What are the advantages and disadvantages of an interest-only loan?
  7. How does the interest rate impact the monthly payment on a loan?
  8. Can you explain how the formula for the annuity payment RR is derived?

Tip: When dealing with interest-only loans, remember that the principal remains the same throughout the loan period, and only the interest is paid periodically.

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Amortization
Interest-only Loans

Formulas

Compound Interest Formula
Loan Balance Formula

Theorems

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Suitable Grade Level

Advanced High School / College Level