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The problem is about calculating the future value of a loan with compound interest, given the following information:

- Principal amount ($ P $) = $2500
- Interest rate ($ r $) = 11% per year (compounded annually)
- Time period ($ t $) is 1 year for part (a) and 2 years for part (b)
- The formula for compound interest is: 
  \[
  A = P \times (1 + r)^t
  \]

### Solution

#### Part (a): Amount owed at the end of 1 year

1. **Substitute the values into the formula:**
   \[
   A = 2500 \times (1 + 0.11)^1
   \]

2. **Calculate the result:**
   \[
   A = 2500 \times 1.11 = 2775
   \]

The amount owed at the end of 1 year is **$2775**.

---

#### Part (b): Amount owed at the end of 2 years

1. **Substitute the values into the formula:**
   \[
   A = 2500 \times (1 + 0.11)^2
   \]

2. **Calculate the result:**
   \[
   A = 2500 \times (1.11)^2 = 2500 \times 1.2321 = 3080.25
   \]

The amount owed at the end of 2 years is **$3080.25**.

---

Let me know if you want further details or have any questions.

### Related Questions:

1. What would be the amount owed at the end of 3 years?
2. How would the owed amount change if the interest were compounded semiannually instead of annually?
3. What is the difference between compound interest and simple interest for this loan over 2 years?
4. How much interest is accrued after the first year?
5. How can we calculate the effective interest rate if compounding occurs more frequently?

#### Tip:
Remember, when interest is compounded annually, it applies once per year on the new principal amount, which includes the accumulated interest.

Supongamos que un préstamo de $2500 se otorga con una tasa de 11% de interés que se capitaliza anualmente. Calcular la cantidad adeudada al final de 1 año y al final de 2 años.

Learn how to calculate the amount owed for a $2500 loan with an 11% interest rate compounded annually. This problem involves compound interest calculations, demonstrating exponential growth over 1 and 2 years.

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