A boy owns 1 pairs of pants, 3 shirts, 4 ties, and 3 jackets. How many different outfits can he wear to school if he must wear one of each item?

To determine the total number of different outfits the boy can wear, we need to consider all possible combinations of pants, shirts, ties, and jackets. Since he must wear one of each item, we can simply multiply the number of choices for each item:

- **Pants**: 1 option
- **Shirts**: 3 options
- **Ties**: 4 options
- **Jackets**: 3 options

The total number of outfits can be calculated as follows:

\[
1 \text{ (pants)} \times 3 \text{ (shirts)} \times 4 \text{ (ties)} \times 3 \text{ (jackets)} = 36 \text{ outfits}
\]

Thus, the boy can wear **36 different outfits**.

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### Related Questions
1. If the boy decided not to wear a tie, how many different outfits could he choose?
2. What would be the total number of outfits if he added another pair of pants?
3. How many different outfits can he make if he chooses to wear any two ties instead of one?
4. What if he wants to include an additional item like a hat, with 2 hat options available?
5. How many combinations are there if he chooses to wear exactly 2 out of the 3 jackets?

### Tip
Always consider the multiplication principle when dealing with independent choices in combinations like this one.

A boy owns 1 pair of pants, 3 shirts, 4 ties, and 3 jackets. How many different outfits can he wear to school if he must wear one of each item?

Find out how many different outfits a boy can wear if he owns 1 pair of pants, 3 shirts, 4 ties, and 3 jackets. Learn the multiplication principle in combinatorics to solve this problem, ideal for students in Grades 5-7.

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