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The question asks: 

"Diego has three pairs of shoes, five pairs of pants, and three shirts. If all items are compatible, how many different outfits can he wear?"

To solve this, we can use the **fundamental principle of counting**, which states that if there are \( n \) independent choices for one item and \( m \) independent choices for another, then the total number of combinations is the product of \( n \) and \( m \).

Here, Diego can choose:
- 3 pairs of shoes
- 5 pairs of pants
- 3 shirts

Thus, the total number of outfits he can wear is:

\[
\text{Total outfits} = 3 \times 5 \times 3 = 45
\]

Diego can wear **45 different outfits**.

Would you like further clarification or details?

Here are 5 related questions for practice:
1. What if Diego had 4 pairs of shoes, 6 pairs of pants, and 2 shirts?
2. How does the fundamental principle of counting apply to real-world scenarios?
3. What would the result be if two items weren't compatible?
4. How would the number of outfits change if Diego added 2 more shirts?
5. What if Diego could wear a jacket in addition to shoes, pants, and shirts, and he had 2 jackets?

**Tip:** The fundamental counting principle is useful in determining combinations in any situation where multiple independent choices are made.

Diego has three pairs of shoes, five pairs of pants, and three shirts. If all items are compatible, how many different outfits can he wear?

Learn how to use the fundamental counting principle to calculate how many different outfits Diego can wear with 3 pairs of shoes, 5 pairs of pants, and 3 shirts. This problem teaches combinatorics and the application of simple multiplication to solve real-world problems. Suitable for Grades 5-7.

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