Math Problem Statement

how long is the minute hand of a clock if it is 7 cm longer than the hour hand, and the distsnce between the tips of the hands at 9 o clock is 13 cm

Solution

Let's denote the length of the hour hand as hh cm and the length of the minute hand as mm cm. According to the problem, the minute hand is 7 cm longer than the hour hand:

m=h+7m = h + 7

At 9 o'clock, the hour hand and the minute hand are perpendicular to each other, forming a right triangle where the hour hand and the minute hand are the legs, and the distance between their tips (13 cm) is the hypotenuse. According to the Pythagorean theorem:

h2+m2=132h^2 + m^2 = 13^2

Substituting m=h+7m = h + 7 into the equation:

h2+(h+7)2=169h^2 + (h + 7)^2 = 169

Now, let's expand and simplify this equation:

h2+(h2+14h+49)=169h^2 + (h^2 + 14h + 49) = 169 2h2+14h+49=1692h^2 + 14h + 49 = 169

Subtract 169 from both sides:

2h2+14h120=02h^2 + 14h - 120 = 0

Now, divide the entire equation by 2:

h2+7h60=0h^2 + 7h - 60 = 0

This is a quadratic equation. We can solve it using the quadratic formula:

h=b±b24ac2ah = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

For our equation, a=1a = 1, b=7b = 7, and c=60c = -60. Plugging in the values:

h=7±72+2402h = \frac{-7 \pm \sqrt{7^2 + 240}}{2} h=7±2892h = \frac{-7 \pm \sqrt{289}}{2} h=7±172h = \frac{-7 \pm 17}{2}

This gives us two possible solutions for hh:

h=102=5orh=242=12h = \frac{10}{2} = 5 \quad \text{or} \quad h = \frac{-24}{2} = -12

Since hh must be positive, h=5h = 5 cm.

Now, using m=h+7m = h + 7:

m=5+7=12 cmm = 5 + 7 = 12 \text{ cm}

Thus, the length of the minute hand is 12 cm.

Would you like more details or have any questions?

Here are some related questions you might find interesting:

  1. How would the problem change if the distance between the tips was different?
  2. What is the formula for calculating the distance between the tips at any other time?
  3. How would you solve the problem if the lengths of both hands were unknown?
  4. What would the hour hand length be if the minute hand were 5 cm longer?
  5. What other configurations lead to a right triangle between the clock hands?
  6. How does the minute hand length affect the speed of the clock?
  7. Can you generalize the problem to solve for any time?
  8. How does the Pythagorean theorem apply to other time intervals?

Tip: Always check the feasibility of your solutions in the context of the problem to avoid unrealistic results.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Quadratic Equations

Formulas

Pythagorean theorem
Quadratic formula

Theorems

Pythagorean theorem

Suitable Grade Level

Grades 7-9