Math Problem Statement

Find the circumference and area of the adjacent circle. Use the pi key for pi. 14 " Question content area bottom Part 1 The circumference of the circle is approximately    enter your response here ▼ in. in. squared ​(Type an integer or decimal rounded to the nearest tenth as​ needed.) Part 2 The area of the circle is approximately    enter your response here ▼ in. squared in. ​(Type an integer or decimal rounded to the nearest tenth as​ needed.)

Solution

To find the circumference and area of a circle with a diameter of 14 inches, we can use the following formulas:

  1. Circumference (C)(C): C=π×dC = \pi \times d where d=14d = 14 inches.

    Substituting the values: C=π×1443.98 inchesC = \pi \times 14 \approx 43.98 \text{ inches}

    Rounding to the nearest tenth: C44.0 inchesC \approx 44.0 \text{ inches}

  2. Area (A)(A): A=π×r2A = \pi \times r^2 where rr is the radius. Since the diameter is 14 inches, the radius r=142=7r = \frac{14}{2} = 7 inches.

    Substituting the values: A=π×72=π×49153.94 square inchesA = \pi \times 7^2 = \pi \times 49 \approx 153.94 \text{ square inches}

    Rounding to the nearest tenth: A153.9 square inchesA \approx 153.9 \text{ square inches}

Answers:

  • Circumference: 44.0 inches
  • Area: 153.9 square inches

Would you like further details on this calculation, or do you have any other questions?


Here are some related questions for deeper understanding:

  1. What would the circumference be if the diameter were doubled?
  2. How would the area change if the radius were tripled?
  3. Can you express the answers in terms of π\pi instead of approximating it?
  4. How does the area relate to the square of the radius, and why?
  5. What are the practical applications of calculating circumference and area?

Tip: Remember that the area formula πr2\pi r^2 depends heavily on the radius, making small changes in radius lead to large area differences due to the square factor.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circles
Circumference
Area

Formulas

Circumference of a circle: C = π × d
Area of a circle: A = π × r^2

Theorems

Circle Properties

Suitable Grade Level

Grades 6-8