Math Problem Statement

少数で求めてください

少数で求めてください

Solution

The summation formula shown in the image appears to calculate the expected value of a binomial random variable scaled by kxkx. Here's the formula:

k=030k(30k)(112)k(1112)30k.\sum_{k=0}^{30} k \cdot \binom{30}{k} \cdot \left( \frac{1}{12} \right)^k \cdot \left( \frac{11}{12} \right)^{30-k}.

To solve this:

Step 1: Recognize this as a property of the binomial distribution.

The formula simplifies using the expectation property of the binomial distribution:

  • A binomial random variable XB(n,p)X \sim B(n, p) has E[X]=npE[X] = n \cdot p.

Here:

  • n=30n = 30 (number of trials),
  • p=112p = \frac{1}{12} (probability of success).

Step 2: Simplify the summation.

Using the expected value property: E[X]=30112=2.5.E[X] = 30 \cdot \frac{1}{12} = 2.5.

Since kx=kk \cdot x = k, the answer is directly the expectation: 2.52.5

Let me know if you want further details or explanations!


Questions:

  1. How is the expectation of a binomial distribution derived mathematically?
  2. What does the summation property in the binomial distribution indicate?
  3. How can this problem be solved computationally for larger values of nn?
  4. What are the practical applications of binomial distributions in probability?
  5. How does changing pp to other fractions affect the expected value?

Tip:

For binomial summations involving k(nk)k \cdot \binom{n}{k}, use the expectation formula E[X]=npE[X] = n \cdot p to simplify your calculations!

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Math Problem Analysis

Mathematical Concepts

Probability
Binomial Distribution
Expected Value

Formulas

E[X] = n * p (Expected value of a binomial distribution)
Binomial coefficient: C(n, k) = n! / (k! * (n-k)!)

Theorems

The expectation theorem for a binomial random variable
Binomial expansion theorem

Suitable Grade Level

Undergraduate Level