Math Problem Statement

A 3/4 in shaft uses sleeve bearings. The total load per bearing is 400 lb. An L/D ratio of 2.5 is desired. What is the bearing pressure in psi?

Solution

To find the bearing pressure, we can use the following formula:

Bearing Pressure=LoadBearing Area\text{Bearing Pressure} = \frac{\text{Load}}{\text{Bearing Area}}

Step 1: Determine the Bearing Area

The bearing area is the product of the bearing's length (L) and the shaft diameter (D). Since the length-to-diameter (L/D) ratio is provided, we can calculate the length as:

L=L/D×DL = \text{L/D} \times D

Given that:

  • Diameter (D) = 3/4 inches = 0.75 inches
  • L/D ratio = 2.5

L=2.5×0.75=1.875inchesL = 2.5 \times 0.75 = 1.875 \, \text{inches}

Step 2: Calculate the Bearing Area

The bearing area (A) is the product of the length and the diameter:

A=L×D=1.875inches×0.75inches=1.40625square inchesA = L \times D = 1.875 \, \text{inches} \times 0.75 \, \text{inches} = 1.40625 \, \text{square inches}

Step 3: Calculate the Bearing Pressure

Now, we can calculate the bearing pressure:

Bearing Pressure=400lb1.40625square inches=284.21psi\text{Bearing Pressure} = \frac{400 \, \text{lb}}{1.40625 \, \text{square inches}} = 284.21 \, \text{psi}

Thus, the bearing pressure is approximately 284.21 psi.

Would you like further clarification on any part of this?

Here are some related questions:

  1. What are common L/D ratios for different applications?
  2. How does bearing pressure affect bearing wear?
  3. What materials are suitable for sleeve bearings in high-pressure situations?
  4. How can increasing the bearing length affect the load capacity?
  5. What are the effects of misalignment in sleeve bearings?

Tip: Maintaining proper lubrication in sleeve bearings is essential for minimizing wear and extending their life.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pressure Calculation
Ratios

Formulas

Bearing Pressure = Load / Bearing Area
L = (L/D) * D
Bearing Area = L * D

Theorems

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Suitable Grade Level

College Level (Engineering/Physics)