Consider a BJT with an emitter injection efficiency of 0.9995 and a DC current gain (β) of 50. Calculate the base transport factor

0.99
 

0.98
 

0.95
 

1.01

The base transport factor (\( \alpha_T \)) in a Bipolar Junction Transistor (BJT) relates to how well the injected carriers are transported across the base without recombining. It is defined by the following relationship:

\[
\alpha_T = \frac{\beta}{\beta + 1} \times \text{Emitter Injection Efficiency} (\gamma)
\]

Given:
- \( \beta = 50 \)
- Emitter Injection Efficiency (\( \gamma \)) = 0.9995

First, we calculate the transport factor:

\[
\alpha_T = \frac{50}{50 + 1} \times 0.9995 = \frac{50}{51} \times 0.9995
\]

Let's compute this value.

\[
\alpha_T \approx 0.9804
\]

Thus, the base transport factor is approximately **0.98**.

### Final answer: 0.98

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Would you like more details or have any questions?

Here are 5 related questions to further explore the topic:
1. How does the base width affect the base transport factor?
2. What is the physical significance of emitter injection efficiency in a BJT?
3. How does the base transport factor impact the overall performance of a BJT?
4. How is the current gain \( \beta \) related to the base transport factor and emitter injection efficiency?
5. What are typical values of emitter injection efficiency in high-performance BJTs?

**Tip:** In high-gain BJTs, reducing base recombination helps improve both current gain and the base transport factor.

Consider a BJT with an emitter injection efficiency of 0.9995 and a DC current gain (β) of 50. Calculate the base transport factor.

Learn how to calculate the base transport factor of a Bipolar Junction Transistor (BJT) with an emitter injection efficiency of 0.9995 and a DC current gain (β) of 50. This problem involves key concepts such as emitter injection efficiency, base transport factor, and BJT current gain. Suitable for undergraduate students studying electronics or semiconductor physics.

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