The base transport factor ($\alpha_T$) in a Bipolar Junction Transistor (BJT) relates to how well the injected carriers are transported across the base without recombining. It is defined by the following relationship:

$\alpha_T = \frac{\beta}{\beta + 1} \times \text{Emitter Injection Efficiency} (\gamma)$

Given:

• $\beta = 50$
• Emitter Injection Efficiency ($\gamma$) = 0.9995

First, we calculate the transport factor:

$\alpha_T = \frac{50}{50 + 1} \times 0.9995 = \frac{50}{51} \times 0.9995$

Let's compute this value.

$\alpha_T \approx 0.9804$

Thus, the base transport factor is approximately 0.98.

Final answer: 0.98

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Would you like more details or have any questions?

Here are 5 related questions to further explore the topic:

1. How does the base width affect the base transport factor?
2. What is the physical significance of emitter injection efficiency in a BJT?
3. How does the base transport factor impact the overall performance of a BJT?
4. How is the current gain $\beta$ related to the base transport factor and emitter injection efficiency?
5. What are typical values of emitter injection efficiency in high-performance BJTs?

Tip: In high-gain BJTs, reducing base recombination helps improve both current gain and the base transport factor.