vavg = (Δx1 + Δx2)/(t1 + t2)

You have a first displacement of Δx1 = -2.2 m, and a first  time of t1 = 7.4 s.  You have a second displacement of Δx2 = -11.6 m, and a second time of t2 = 10.9 s. What is the average velocity vavg?  Answer with two decimal places.

# Let's calculate the average velocity (vavg) using the given formula and values.

# Given values:
delta_x1 = -2.2  # first displacement in meters
t1 = 7.4  # first time in seconds
delta_x2 = -11.6  # second displacement in meters
t2 = 10.9  # second time in seconds

# Formula for average velocity:
vavg = (delta_x1 + delta_x2) / (t1 + t2)

# Calculating the average velocity and rounding to two decimal places
vavg_rounded = round(vavg, 2)
vavg_roundedThe average velocity \( v_{\text{avg}} \) is \(-0.75 \, \text{m/s}\).

Would you like more details, or do you have any other questions? 

Here are some related questions you might find interesting:
1. How would the average velocity change if the time intervals were different?
2. What is the significance of a negative average velocity?
3. How would you calculate the average speed instead of velocity?
4. How does average velocity differ from instantaneous velocity?
5. Can average velocity be zero even if there is displacement?

**Tip:** Always pay attention to the signs of displacement values, as they indicate direction.

You have a first displacement of Δx1 = -2.2 m, and a first time of t1 = 7.4 s. You have a second displacement of Δx2 = -11.6 m, and a second time of t2 = 10.9 s. What is the average velocity vavg? Answer with two decimal places.

Learn how to calculate the average velocity given two displacements (Δx1 = -2.2 m, Δx2 = -11.6 m) and their corresponding time intervals (t1 = 7.4 s, t2 = 10.9 s). This problem demonstrates key concepts in kinematics and is suitable for students in Grades 9-12.

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