To find the average acceleration of the roller coaster car, we can use the following formula for average acceleration $a$:

$a = \frac{\Delta v}{\Delta t}$

Where:

• $\Delta v$ is the change in velocity (final velocity - initial velocity)
• $\Delta t$ is the time interval during which the change occurs.

Given:

• Initial velocity, $v_0 = 4 \, \text{m/s}$
• Final velocity, $v = 22 \, \text{m/s}$
• Time interval, $\Delta t = 3 \, \text{seconds}$

Now, calculate the change in velocity: $\Delta v = 22 \, \text{m/s} - 4 \, \text{m/s} = 18 \, \text{m/s}$

Now, calculate the average acceleration: $a = \frac{18 \, \text{m/s}}{3 \, \text{s}} = 6 \, \text{m/s}^2$

Answer:

The average acceleration of the roller coaster car is $6 \, \text{m/s}^2$.

Would you like more details or explanations on this topic?

Here are 5 related questions for deeper understanding:

1. What is the difference between average acceleration and instantaneous acceleration?
2. How would the acceleration change if the time interval were doubled?
3. What is the significance of negative acceleration, or deceleration?
4. How can we calculate the distance traveled during this time with constant acceleration?
5. Can you explain the relationship between acceleration and force in this scenario?

Tip: When acceleration is constant, the change in velocity is linear with time!