Find the area of the triangle with base 2/9 and height 7/9 

To find the area of a triangle, you use the formula:

\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]

Given the base is \( \frac{2}{9} \) and the height is \( \frac{7}{9} \), the area is calculated as follows:

\[
\text{Area} = \frac{1}{2} \times \frac{2}{9} \times \frac{7}{9}
\]

First, multiply the fractions:

\[
\frac{2}{9} \times \frac{7}{9} = \frac{2 \times 7}{9 \times 9} = \frac{14}{81}
\]

Now, multiply by \( \frac{1}{2} \):

\[
\text{Area} = \frac{1}{2} \times \frac{14}{81} = \frac{14}{162}
\]

Finally, simplify the fraction if possible. The greatest common divisor (GCD) of 14 and 162 is 2, so:

\[
\frac{14}{162} = \frac{7}{81}
\]

Thus, the area of the triangle is \( \frac{7}{81} \).

Would you like more details or have any questions?

Here are 5 related questions to consider:
1. How do you simplify complex fractions?
2. What is the formula for the area of a triangle when given different types of measurements?
3. How do you find the area of a triangle with non-fractional dimensions?
4. How does changing the base or height affect the area of a triangle?
5. Can you find the area of other shapes using similar methods?

**Tip:** When dealing with fractions in geometric formulas, it helps to simplify the fractions at each step to avoid large numbers and make calculations easier.

Learn how to calculate the area of a triangle with a base of 2/9 and a height of 7/9 using the formula for the area of a triangle. This problem involves understanding geometric concepts and fraction arithmetic. Suitable for students in Grades 6-8.

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