A. \frac{1}{2}\left(9\right)\left(15\right)\cos(20^{\circ}) B. \frac{1}{2}\left(11\right)\left(15\right)\sin(20^{\circ}) C. \frac{1}{2}\left(9\right)\left(15\right)\sin(20^{\circ}) D. \frac{1}{2}\left(11\right)\left(15\right)\cos(20^{\circ})

Let's analyze the expressions provided and see which one correctly represents the area of triangle \( QRS \).

### Formula for the area of a triangle:
For a triangle with two sides and an angle between them, the area can also be calculated using the formula:

\[
\text{Area} = \frac{1}{2} \times a \times b \times \sin(C)
\]

where:
- \( a \) and \( b \) are two sides of the triangle,
- \( C \) is the angle between them.

In triangle \( QRS \), we have:
- The hypotenuse \( RS = 15 \),
- The base \( RQ = 9 \),
- The angle \( \angle R = 20^\circ \).

Since \( RQ \) and \( RS \) form the angle \( 20^\circ \), we can use the formula for the area:

\[
\text{Area} = \frac{1}{2} \times RQ \times RS \times \sin

Explore how to calculate the area of triangle QRS using the formula for the area of a triangle with two sides and the included angle. Given sides RQ = 9 and RS = 15, and angle R = 20 degrees, find the correct expression among A, B, C, or D. Suitable for high school students.

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