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The problem in the image asks about an 8-inch-by-6-inch rectangle that is cut along a diagonal to form two triangles. We are asked to find the area of each triangle in square inches.

### Solution:

The area of the entire rectangle is:
\[
\text{Area of rectangle} = \text{length} \times \text{width} = 8 \times 6 = 48 \text{ square inches}
\]

When the rectangle is cut along a diagonal, it forms two triangles. Since the diagonal divides the rectangle into two congruent (equal) triangles, the area of each triangle is half the area of the rectangle.

Thus, the area of each triangle is:
\[
\text{Area of each triangle} = \frac{48}{2} = 24 \text{ square inches}
\]

The correct answer is **J. 24**.

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:
1. How do you find the area of a triangle given its base and height?
2. What is the formula for the area of a right triangle?
3. How would you calculate the area of each triangle if the rectangle had different dimensions?
4. If the rectangle was cut into four triangles instead of two, what would the area of each triangle be?
5. How would the area change if the rectangle was cut along a different diagonal?

**Tip:** The area of a triangle can always be found using the formula \( \frac{1}{2} \times \text{base} \times \text{height} \), which is especially useful in geometry problems involving triangles.

An 8-inch-by-6-inch rectangle is cut along a diagonal to form two triangles. What is the area, in square inches, of each triangle?

Learn how to calculate the area of each triangle when an 8-inch-by-6-inch rectangle is cut along its diagonal. This problem demonstrates key geometry concepts and formulas. Suitable for Grades 6-8 students.

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