Math Problem Statement

Solution

To solve this problem, let's follow these steps:

  1. Understand the figure and given information:

    • ABCD is a trapezoid with ADBCAD \parallel BC.
    • E, F, and G are midpoints of AD, BC, and DC respectively.
    • The areas of the triangles ABE\triangle ABE, EGD\triangle EGD, and GFC\triangle GFC are provided as 2, 5, and 6 respectively.
  2. Determine the method:

    • We'll use the areas given and properties of midpoints to find the area of the shaded region EGF\triangle EGF.
  3. Calculations:

Let's denote the area of the trapezoid ABCD as AABCDA_{ABCD}.

  • Since E and F are midpoints, EFEF is parallel to ADAD and BCBC, and EFEF is the midsegment of the trapezoid.

Using the properties of midsegments, the area of EGF\triangle EGF can be calculated as follows:

  • The shaded area EGF\triangle EGF is composed of parts of triangles formed by connecting midpoints.

  • The total area of triangles ABE\triangle ABE, EGD\triangle EGD, and GFC\triangle GFC plus the area of the shaded region EGF\triangle EGF should equal the total area of the trapezoid ABCDABCD.

Given: Area of ABE=2\text{Area of } \triangle ABE = 2 Area of EGD=5\text{Area of } \triangle EGD = 5 Area of GFC=6\text{Area of } \triangle GFC = 6

Let's denote the area of the shaded region EGF\triangle EGF as AEGFA_{EGF}.

The total area of the trapezoid ABCD: AABCD=2+5+6+AEGFA_{ABCD} = 2 + 5 + 6 + A_{EGF}

Notice that the trapezoid is divided into 4 regions. The area of the trapezoid is twice the sum of the areas of these triangles because E, F, and G are midpoints: AABCD=2×(2+5+6)A_{ABCD} = 2 \times (2 + 5 + 6)

Thus: 2×(2+5+6)=2×13=262 \times (2 + 5 + 6) = 2 \times 13 = 26

So, the equation is: 26=2+5+6+AEGF26 = 2 + 5 + 6 + A_{EGF}

26=13+AEGF26 = 13 + A_{EGF}

AEGF=2613=13A_{EGF} = 26 - 13 = 13

Therefore, the area of the shaded region EGF\triangle EGF is 13\boxed{13}.

Would you like further details or have any questions about this solution?

Here are some questions you might ask next:

  1. How do midpoints affect the division of areas in geometric shapes?
  2. What other properties of trapezoids can be useful in area calculations?
  3. Can this method be applied to other types of quadrilaterals?
  4. What role do parallel lines play in area determination?
  5. Are there other methods to find the area of the shaded region?

Tip: When solving geometric problems, always look for symmetrical properties and relationships between midpoints and parallel lines.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area of Trapezoids
Midpoints

Formulas

Area of Trapezoid
Properties of Midsegments

Theorems

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Suitable Grade Level

Grades 9-12