To find the area of a rectangle, you multiply the width by the length.

Given:

• Width = $\frac{2}{9}$ inches
• Length = $\frac{6}{10}$ inches

The area $A$ of the rectangle is calculated as:

$A = \text{Width} \times \text{Length} = \frac{2}{9} \times \frac{6}{10}$

Multiply the numerators together and the denominators together:

$A = \frac{2 \times 6}{9 \times 10} = \frac{12}{90}$

Now, simplify the fraction $\frac{12}{90}$:

$\frac{12}{90} = \frac{2 \times 6}{2 \times 45} = \frac{6}{45}$

Simplify further by dividing both the numerator and the denominator by 3:

$\frac{6}{45} = \frac{2}{15}$

So, the area of the rectangle is $\frac{2}{15}$ square inches.

Would you like more details or have any other questions?

Here are 5 related questions you might find interesting:

1. How would the area change if the width was doubled?
2. What is the perimeter of the same rectangle?
3. If the width is changed to $\frac{4}{9}$ inches, what would the new area be?
4. How do you convert $\frac{2}{15}$ square inches to a decimal?
5. How would you find the area of a square with the same perimeter as this rectangle?

Tip: Always simplify fractions when possible to make your final answer more understandable.