What is the area of a rectangle if the width is 2/9 inches and the length is 6/10 inches?

To find the area of a rectangle, you multiply the width by the length.

Given:
- Width = \( \frac{2}{9} \) inches
- Length = \( \frac{6}{10} \) inches

The area \( A \) of the rectangle is calculated as:

\[
A = \text{Width} \times \text{Length} = \frac{2}{9} \times \frac{6}{10}
\]

Multiply the numerators together and the denominators together:

\[
A = \frac{2 \times 6}{9 \times 10} = \frac{12}{90}
\]

Now, simplify the fraction \( \frac{12}{90} \):

\[
\frac{12}{90} = \frac{2 \times 6}{2 \times 45} = \frac{6}{45}
\]

Simplify further by dividing both the numerator and the denominator by 3:

\[
\frac{6}{45} = \frac{2}{15}
\]

So, the area of the rectangle is \( \frac{2}{15} \) square inches.

Would you like more details or have any other questions?

Here are 5 related questions you might find interesting:
1. How would the area change if the width was doubled?
2. What is the perimeter of the same rectangle?
3. If the width is changed to \( \frac{4}{9} \) inches, what would the new area be?
4. How do you convert \( \frac{2}{15} \) square inches to a decimal?
5. How would you find the area of a square with the same perimeter as this rectangle?

**Tip:** Always simplify fractions when possible to make your final answer more understandable.

Learn how to calculate the area of a rectangle with fractions. Given a width of 2/9 inches and a length of 6/10 inches, find the area step-by-step. Suitable for students in Grades 4-6, covering key concepts in geometry and fractions.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation