To find the area of the quadrilateral $EFGH$, we can break it into two simpler shapes:

1. A large rectangle $EGH$ with:

   • Base = 10 cm
   • Height = 5 cm
   • Area = $10 \times 5 = 50$ cm²

2. A smaller right triangle $FGH$ with:

   • Base = 10 cm
   • Height = $5 - 2 = 3$ cm
   • Area = $\frac{1}{2} \times 10 \times 3 = 15$ cm²

Now, subtract the triangle's area from the rectangle's area:

$50 - 15 = 35 \text{ cm}^2$

So, the area of the quadrilateral is 35.0 cm² (rounded to 1 decimal place).

Would you like a step-by-step explanation?

Related Questions:

1. How do you find the area of a trapezium?
2. What formula is used to find the area of a right triangle?
3. How do you calculate the perimeter of the given quadrilateral?
4. What other methods can be used to find the area of an irregular quadrilateral?
5. How would the area change if $F$ were higher or lower?

Tip:

Breaking complex shapes into rectangles and triangles often makes calculations easier!