To solve for $A$ in the equation $\frac{bh}{2} = A$, you're given a formula commonly used to calculate the area of a triangle, where:

• $b$ represents the base of the triangle,
• $h$ represents the height of the triangle,
• $A$ represents the area.

The formula is already solved for $A$, so:

$A = \frac{bh}{2}$

This equation tells you that the area $A$ of a triangle is equal to half of the product of its base $b$ and height $h$.

Do you need more details on how to use this formula, or any other clarification?

Here are 5 related questions to expand on this:

1. How do you calculate the base or height if the area $A$ is given?
2. How does the formula change for different types of triangles (e.g., right, isosceles)?
3. What is the relationship between the area formula and trigonometric functions for non-right triangles?
4. Can you derive the same formula using coordinate geometry?
5. How do the dimensions of the triangle affect the area as $b$ and $h$ change?

Tip: When solving for unknowns in equations, make sure all units are consistent to avoid errors in your final answer.