To solve for \( A \) in the equation \( \frac{bh}{2} = A \), you're given a formula commonly used to calculate the area of a triangle, where:

- \( b \) represents the base of the triangle,
- \( h \) represents the height of the triangle,
- \( A \) represents the area.

The formula is already solved for \( A \), so:

\[
A = \frac{bh}{2}
\]

This equation tells you that the area \( A \) of a triangle is equal to half of the product of its base \( b \) and height \( h \).

Do you need more details on how to use this formula, or any other clarification?

Here are 5 related questions to expand on this:

1. How do you calculate the base or height if the area \( A \) is given?
2. How does the formula change for different types of triangles (e.g., right, isosceles)?
3. What is the relationship between the area formula and trigonometric functions for non-right triangles?
4. Can you derive the same formula using coordinate geometry?
5. How do the dimensions of the triangle affect the area as \( b \) and \( h \) change?

**Tip:** When solving for unknowns in equations, make sure all units are consistent to avoid errors in your final answer.

Understand how to calculate the area of a triangle using the formula A = (bh) / 2, where b represents the base and h the height. This concept is key in geometry for students in Grades 6-8. Explore related topics like solving for unknowns and variations of the formula for different types of triangles.

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