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To find the area of a trapezoid, we use the formula:

\[
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
\]

where:
- \( b_1 \) is the length of the top base,
- \( b_2 \) is the length of the bottom base, and
- \( h \) is the height.

For this trapezoid:
- \( b_1 = 5 \, \text{mm} \)
- \( b_2 = 15 \, \text{mm} \)
- \( h = 6 \, \text{mm} \)

Now, substitute these values into the formula:

\[
\text{Area} = \frac{1}{2} \times (5 + 15) \times 6
\]

Simplify inside the parentheses:

\[
= \frac{1}{2} \times 20 \times 6
\]

Then multiply:

\[
= \frac{1}{2} \times 120 = 60 \, \text{mm}^2
\]

### Answer:
The area of the trapezoid is \( 60 \, \text{mm}^2 \).

Would you like more details, or do you have any questions?

Here are some related questions:
1. How would the area change if the height were doubled?
2. What is the formula for the perimeter of a trapezoid?
3. How does the area formula change if one of the bases is zero (making it a triangle)?
4. How is the area of a trapezoid related to the area of a rectangle?
5. How can you find the area of a trapezoid if only the diagonals and height are known?

**Tip:** Remember to add both bases before multiplying by the height when calculating the area of a trapezoid.

Find the area of the trapezoid with bases b1 = 5 mm, b2 = 15 mm, and height h = 6 mm.

Learn how to calculate the area of a trapezoid with bases b1 = 5 mm, b2 = 15 mm, and height h = 6 mm. This geometry problem is ideal for students in Grades 6-8, covering the area calculation formula for trapezoids.

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