Draw a rectangle of side 6cm 4cm and Draw a rectangle of same area of width 7 cm

To solve the problem, we first need to determine the area of the initial rectangle and then use that area to find the length of the second rectangle with a width of 7 cm.

### Step 1: Calculate the area of the first rectangle.
The area \( A \) of a rectangle is given by:
\[
A = \text{length} \times \text{width}
\]

For the first rectangle:
- Length = 6 cm
- Width = 4 cm

\[
A = 6 \times 4 = 24 \, \text{cm}^2
\]

### Step 2: Determine the length of the second rectangle.
Given that the area of the second rectangle is also 24 cm² and its width is 7 cm, we can find the length \( L \) using the formula:
\[
L = \frac{A}{\text{width}}
\]

\[
L = \frac{24}{7} \approx 3.43 \, \text{cm}
\]

### Step 3: Draw the rectangles
- **First Rectangle**: A rectangle with a length of 6 cm and a width of 4 cm.
- **Second Rectangle**: A rectangle with a width of 7 cm and a length of approximately 3.43 cm, both having the same area of 24 cm².

Would you like to see a visual representation of these rectangles? If you need any more details, feel free to ask!

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Here are five questions related to this problem:

1. How would the area change if the first rectangle's width were doubled?
2. What would the new width be if we kept the area of 24 cm² and the length at 5 cm?
3. How would you calculate the perimeter of both rectangles?
4. Can you think of a rectangle with the same perimeter as the first rectangle but a different area?
5. What happens to the area if both the length and width of a rectangle are doubled?

**Tip:** When solving for the length or width of a rectangle with a known area, always ensure the other dimension is accurately measured or calculated.

Learn how to calculate the area of rectangles with different dimensions. Solve problems involving rectangles with specific lengths and widths, ensuring both have the same area. Suitable for students in Grades 4-6.

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