To find the area of this irregular figure, we can break it down into simpler shapes—rectangles and triangles—and sum up their areas.

Breakdown of the figure:

1. Bottom-left rectangle:

   • Dimensions: $28 \, \text{yd} \times 8 \, \text{yd}$
   • Area = $28 \times 8 = 224 \, \text{yd}^2$

2. Middle-left rectangle:

   • Dimensions: $14 \, \text{yd} \times 8 \, \text{yd}$
   • Area = $14 \times 8 = 112 \, \text{yd}^2$

3. Middle-top rectangle:

   • Dimensions: $8 \, \text{yd} \times 8 \, \text{yd}$
   • Area = $8 \times 8 = 64 \, \text{yd}^2$

4. Top-right rectangle:

   • Dimensions: $6 \, \text{yd} \times 8 \, \text{yd}$
   • Area = $6 \times 8 = 48 \, \text{yd}^2$

5. Right triangle (bottom right):

   • Base = 26 yd, Height = 8 yd
   • Area = $\frac{1}{2} \times 26 \times 8 = 104 \, \text{yd}^2$

Total Area:

Now, sum the areas of all these parts:

$224 + 112 + 64 + 48 + 104 = 552 \, \text{yd}^2$

Thus, the area of the figure is 552 square yards.

Would you like more details on the steps, or do you have any questions?

Related questions:

1. How do you calculate the area of irregular shapes in general?
2. What is the formula for the area of a triangle?
3. How would the approach change if the shape included a circle?
4. What is the significance of using approximate values like 3.14 for pi in geometry?
5. How would you handle more complex polygons that cannot easily be broken into rectangles or triangles?

Tip:

When dealing with complex shapes, always try to break them down into simpler geometric figures (rectangles, triangles, circles) for easier calculation.