To solve for the area of this figure, we can break it down into simpler geometric shapes: a rectangle and a triangle.

1. The Rectangle:

   • The base is 48 m, and the height is 10 m.
   • The area of a rectangle is given by: $\text{Area of rectangle} = \text{base} \times \text{height}$ $= 48 \, \text{m} \times 10 \, \text{m} = 480 \, \text{m}^2$

2. The Triangle:

   • The base of the triangle is 48 m (the same as the rectangle's base), but this triangle is composed of two smaller right triangles. Each smaller right triangle has:

     • Base of 25 m.
     • Height of 17 m - 10 m = 7 m (this is because the total height from the base to the top is 17 m, and we subtract the 10 m height of the rectangle part).

   • The area of one right triangle is: $\text{Area of one triangle} = \frac{1}{2} \times \text{base} \times \text{height}$ $= \frac{1}{2} \times 25 \, \text{m} \times 7 \, \text{m} = 87.5 \, \text{m}^2$

   • Since there are two such triangles: $\text{Total area of triangles} = 2 \times 87.5 \, \text{m}^2 = 175 \, \text{m}^2$

3. Total Area:

   • Adding the areas of the rectangle and the triangles: $\text{Total Area} = 480 \, \text{m}^2 + 175 \, \text{m}^2 = 655 \, \text{m}^2$

Thus, the area of the figure is 655 square meters.

Would you like more details or have any questions about this? Here are some related questions you might find helpful:

1. How do you calculate the area of irregular shapes?
2. What is the formula for the area of a right triangle?
3. How do you decompose complex figures into simpler shapes?
4. Why is the height of the triangle calculated as $17 \, \text{m} - 10 \, \text{m}$?
5. What other methods can be used to find the area of composite figures?

Tip: When solving geometry problems, always look for ways to break complex shapes into simpler, well-known geometric figures like rectangles and triangles.