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To calculate the area of the shape shown (a circular piece of paper with a smaller circular hole cut out), we need to:

1. Find the area of the larger circle (radius = 11 cm).
2. Find the area of the smaller circle (radius = 5 cm).
3. Subtract the area of the smaller circle from the area of the larger circle to get the area of the shape.

### Step 1: Area of the larger circle
The formula for the area of a circle is:
\[
A = \pi r^2
\]
For the larger circle, \( r = 11 \, \text{cm} \):
\[
A_{\text{large}} = \pi \times 11^2 = \pi \times 121 \approx 380.13 \, \text{cm}^2
\]

### Step 2: Area of the smaller circle
For the smaller circle, \( r = 5 \, \text{cm} \):
\[
A_{\text{small}} = \pi \times 5^2 = \pi \times 25 \approx 78.54 \, \text{cm}^2
\]

### Step 3: Subtract the areas
Now subtract the area of the smaller circle from the area of the larger circle:
\[
\text{Area of the shape} = 380.13 - 78.54 = 301.59 \, \text{cm}^2
\]

### Final Answer
The area of the shape is approximately **301.6 cm²** (rounded to 1 decimal place).

Do you want further details or have any questions?

Here are 5 related questions:
1. What would be the area if the radius of the hole was 7 cm instead?
2. How does changing the radius of the larger circle affect the final area?
3. How can you calculate the circumference of both circles?
4. What is the relationship between the area and the radius in a circle?
5. Can you calculate the area of a sector of the larger circle if part of it was cut out?

**Tip:** Always remember to subtract the area of the smaller circle from the larger one when dealing with ring-like shapes (annuli).

Jared has a circular piece of paper with a radius of 11 cm. He cuts a circular hole with a radius of 5 cm in the center of his piece of paper to make the shape shown. Calculate the area of this shape. Give your answer in cm² to 1 d.p.

Solve the geometry problem involving a circular piece of paper with a radius of 11 cm and a hole with a radius of 5 cm. Learn how to calculate the area of this shape using the formula for the area of a circle and subtracting the inner circle's area.

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