Math Problem Statement

A laboratory in Alaska is interested in finding the mean chloride level for a healthy resident in the state. A random sample of 90 healthy residents has a mean chloride level of 103 mEq L If it is known that the chloride leveis in healthy individuals residing in Alaska have a standard deviation of 40 confidence interval for the true mean chloride level of all healthy Alaska residents. Then give its lower limit and upper limit. mEq L find a 99%

Carry your intermediate computations to least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.)

Lower limit:

Upper limit:

Solution

To find the 99% confidence interval for the true mean chloride level of all healthy Alaska residents, we'll follow these steps:

Step 1: Identify the Given Information

  • Sample mean xˉ=103\bar{x} = 103 mEq/L
  • Population standard deviation σ=40\sigma = 40 mEq/L
  • Sample size n=90n = 90
  • Confidence level = 99%

Step 2: Find the Critical Value

Since the population standard deviation is known and the sample size is large (n30n \geq 30), we will use the Z-distribution to find the critical value.

For a 99% confidence level, the critical value Zα/2Z_{\alpha/2} can be found using a Z-table or standard normal distribution calculator. The value for a 99% confidence level is approximately Zα/2=2.576Z_{\alpha/2} = 2.576.

Step 3: Calculate the Standard Error

The standard error (SE) of the mean is calculated using the formula:

SE=σnSE = \frac{\sigma}{\sqrt{n}}

Substitute the values:

SE=4090409.4874.216SE = \frac{40}{\sqrt{90}} \approx \frac{40}{9.487} \approx 4.216

Step 4: Calculate the Margin of Error (ME)

The margin of error (ME) is calculated using the formula:

ME=Zα/2×SEME = Z_{\alpha/2} \times SE

Substitute the values:

ME=2.576×4.21610.858ME = 2.576 \times 4.216 \approx 10.858

Step 5: Calculate the Confidence Interval

The confidence interval is calculated using the formula:

Lower limit=xˉME\text{Lower limit} = \bar{x} - ME Upper limit=xˉ+ME\text{Upper limit} = \bar{x} + ME

Substitute the values:

Lower limit=10310.85892.1 mEq/L\text{Lower limit} = 103 - 10.858 \approx 92.1 \text{ mEq/L} Upper limit=103+10.858113.9 mEq/L\text{Upper limit} = 103 + 10.858 \approx 113.9 \text{ mEq/L}

Final Answer:

  • Lower limit: 92.1 mEq/L
  • Upper limit: 113.9 mEq/L

These values give the 99% confidence interval for the true mean chloride level of all healthy Alaska residents.

Would you like more details or have any other questions? Here are some related questions you might find useful:

  1. How does increasing the confidence level affect the width of the confidence interval?
  2. What are the assumptions behind using the Z-distribution for confidence intervals?
  3. How would the confidence interval change if the sample size were smaller?
  4. What role does the standard deviation play in determining the confidence interval?
  5. How can we interpret this confidence interval in the context of the population?

Tip: Always ensure to use a larger sample size when possible, as it narrows the confidence interval, providing a more precise estimate of the population parameter.

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Math Problem Analysis

Mathematical Concepts

Statistics
Confidence Intervals

Formulas

Standard Error
Margin of Error
Confidence Interval

Theorems

Central Limit Theorem

Suitable Grade Level

Advanced High School