Math Problem Statement
Write a program in C to find the approximate value of the following definiteintegral usingSimpson's 1/3 rule:
Solution
Simpson's 1/3 rule is a method for approximating the definite integral of a function. The formula is applied when you have an even number of intervals (which is essential) and it assumes that the curve between points is approximately a parabola. The rule works well for smooth and continuous functions.
The formula for Simpson's 1/3 rule to approximate a definite integral is given by:
Where:
- is the step size, and is the number of subintervals.
- must be even.
Here's a C program that implements Simpson's 1/3 rule for approximating a definite integral.
C Program: Simpson's 1/3 Rule
c#include <stdio.h> #include <math.h> // Define the function to integrate double f(double x) { // Example: f(x) = x^2 (You can modify this function as needed) return x * x; } // Function to implement Simpson's 1/3 Rule double simpsons_one_third(double a, double b, int n) { // n must be even if (n % 2 != 0) { printf("n must be an even integer.\n"); return -1; } double h = (b - a) / n; double sum = f(a) + f(b); // First and last terms // Applying Simpson's 1/3 rule for (int i = 1; i < n; i++) { double x = a + i * h; if (i % 2 == 0) { sum += 2 * f(x); // Even indexed terms } else { sum += 4 * f(x); // Odd indexed terms } } return (h / 3) * sum; } int main() { double a, b; int n; // Input the limits of integration a and b printf("Enter the lower limit a: "); scanf("%lf", &a); printf("Enter the upper limit b: "); scanf("%lf", &b); // Input the number of intervals (must be even) printf("Enter the number of intervals (n must be even): "); scanf("%d", &n); // Call Simpson's 1/3 rule function double result = simpsons_one_third(a, b, n); // Print the result if (result != -1) { printf("The approximate value of the integral is: %lf\n", result); } return 0; }
Steps in the Code:
- Define the function
f(x)
: This is the mathematical function that you're integrating. In this case, it’s set as , but you can modify it for any function. - Simpson's 1/3 Rule implementation: The function
simpsons_one_third(a, b, n)
computes the approximation of the integral using Simpson's rule. - User input: The program asks for the lower limit
a
, the upper limitb
, and the number of intervalsn
. The number of intervalsn
must be even for Simpson's rule to work properly. - Calculation and Output: The program calculates the approximate integral value and prints it.
Example Output:
Enter the lower limit a: 0
Enter the upper limit b: 2
Enter the number of intervals (n must be even): 4
The approximate value of the integral is: 2.666667
This example approximates the integral , which has the exact value .
Would you like further details or clarifications?
Here are some relative questions to deepen your understanding:
- What is the mathematical background behind Simpson's 1/3 rule?
- How can the function
f(x)
be changed for other types of integrals? - Why does Simpson’s 1/3 rule require an even number of intervals?
- What is the difference between Simpson's rule and other numerical integration methods like the trapezoidal rule?
- How does the accuracy of Simpson’s rule compare when increasing the number of intervals?
Tip: Increasing the number of intervals (n) can improve the accuracy of the approximation, but at a higher computational cost.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Numerical Integration
Definite Integral
Simpson's 1/3 Rule
Formulas
I = (h / 3) * [f(a) + 4 * Σ f(x_odd) + 2 * Σ f(x_even) + f(b)]
h = (b - a) / n
Theorems
Simpson's Rule for Numerical Integration
Suitable Grade Level
Undergraduate (Calculus I or Numerical Methods)
Related Recommendation
Integration of x^2 Using Simpson's 3/8 Rule
Numerical Integration of ∫ 3sin(t) from 0 to π using Trapezoidal and Simpson's Rule
Understanding the Trapezoidal Rule and Simpson's Rule for Numerical Integration
Evaluate Definite Integral of sin(x) from π to 3π/2 Using Numerical Methods
Integral of f(x) = 1/(1+x^2) in [-1,1] Using Simpson's Rule (n = 4)